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Rasek [7]
4 years ago
14

Solve. 2x + 12 ≥ 6 x ≥ - 3 x ≤ 3 x ≤ - 3 x ≥ 3

Mathematics
1 answer:
juin [17]4 years ago
7 0

x _>_ -3

2x + 12 \geqslant 6 = 2x \geqslant  - 6 = x \geqslant  - 3

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