After a 15% off sale,some jeans were $11.50.How much were the jeans before the sale?

There are 2 questions pls answer fast

Furkat [3]

Answer:

Q1: B. UHWXUQV

Q2: None of these answers equal 12 so I'll just tell you the answers for all of them in case you mistyped.

a. 66

b. 82

c. 120

d. 109

Im assuming you meant 120. If so, your answer is c.

5 0

2 years ago

A car rental agency charges $120 per week plus $.12 per mile driven. How many miles did you drive if the total charge is $162?

777dan777 [17]

$\boxed{y=120+0.12x}\\
\\
y=162\\
\\
120+0.12x=162\\
\\
0.12x=162-120\\
\\
0.12x=42\\
\\
x=\frac{42}{0.12}\\
\\
\boxed{\boxed{x=350 \ miles}}$

7 0

3 years ago

How many solutions does x²+3x=3 have?

aev [14]

Answer:

2 (real) solutions.

Step-by-step explanation:

A quadratic always has two solutions, whether they are real or complex.

Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).

In the case of

x^2+3x = 3, or

x² + 3x -3 = 0

we apply the quadratic formula to get

x = (-3 +/- sqrt(3^2+4(1)(3))/2

to give the two solutions

{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}

both of which are real.

4 0

2 years ago

An eagle perched 40 ft up in a tree looks down at a 35 degree angle(angle of depression) and spots a vole. How far is the vole f

maria [59]

Answer:

$X=49ft$

Step-by-step explanation:

From the question we are told that:

Height of Eagle $h=40ft$

Angle of depression $\theta=35\textdegree$

Generally the trigonometry equation for diagonal X is mathematically given by

$Cos\theta \textdegree=\frac{Adjacent}{Hypotenuse} }$

$Cos\theta \textdegree=\frac{h}{X} }$

$X=\frac{40}{Cos 35 } }$

$X=48.83ft$

$X=49ft$

3 0

3 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

3 years ago