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Alika [10]
3 years ago
10

After a 15% off sale,some jeans were $11.50.How much were the jeans before the sale?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0
$13.53 is the answer to you problem
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Here is a circle touching a square.
Alex Ar [27]

Answer: 9πcm²

Step-by-step explanation: area of the square= 36cm²

Therefore, the area of one side= √area = √36 = 6cms

Since the circle is touching the sides of the square, the side of the square = the diameter of the circle

Therefore the radius of the circle= side/2 = 3cm

The formula for the ares of the circle is πr²

π*3*3 = 9πcm²

8 0
3 years ago
Factoring Trinomals (a=1)<br>b^2 + 8b + 7
yulyashka [42]
b^2+8b+7=b^2+b+7b+7=b(b+1)+7(b+1)\\\\=\boxed{(b+1)(b+7)}
4 0
3 years ago
What's the rate for a 2,500 principle and a interest of 750 and time 3 years
tekilochka [14]
9.14% is the number rounded to the nearest hundredth
5 0
3 years ago
Need help on the blanks. Pretty lost atm
nlexa [21]

Answer:

  • -108.26
  • -108.13
  • -108.052
  • -108.026
  • -108

Step-by-step explanation:

A graphing calculator or spreadsheet is useful for making the repeated function evaluations required.

The average velocity on the interval [a,b] will be ...

  v avg = (y(b) - y(a))/(b-a)

Here, all the intervals start at a=3, so the average velocity for the given values of t will be ...

  v avg = (y(3+t) -y(3))/((3+t) -3) = (y(3+t) -y(3))/t

This can be computed for each of the t-values given. The results are shown in the attached table.

__

We note that the fractional part of the velocity gets smaller in proportion to t getting smaller. We expect it to go to 0 when t goes to 0.

The estimated instantaneous velocity is -108 ft/s.

_____

We can simplify the average velocity equation to ...

  v avg = ((48(3+t) -26(t+3)^2) -(48(t+3) -26(3)^2)) / t

  = (48t -26(t^2 +6t))/t

  = 48 -26t -156

<em>   v avg = -108 -26t</em>

Then the average velocity at t=0 is -108.

5 0
3 years ago
Yal come on help me pls help me
vlabodo [156]

Answer:

X

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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