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mr Goodwill [35]
3 years ago
8

20 Point!

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

determinant: \sqrt{b^2-4ac}

(a) x^2+4x+5=0\\D=4^2-4\cdot1\cdot5={-4}\\D

D<0 means there are no real roots. there are two complex roots with imaginary components.

(b) D=16+20=36>0

D>0 means there are two real roots

(c) D = 20^2-4*4*25 = 0

D=0 means there is one real root with multiplicity 2


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  10 in

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There are two ways to work this problem, and they give different answers. The reason for that is that <em>the data shown in the diagram is not consistent</em>.

<u>Method 1</u>

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<u>Method 2</u>

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Right of the "?" we have ...

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7 0
3 years ago
Can somebody plz help me out here and answer all these correctly (only if u remmeber how to do this) thx sm! :3
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i do no sorry plz i have exam in online so sorry

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Read 2 more answers
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