The length of the curve 
from x = 3 to x = 6 is 192 units
<h3>How to determine the length of the curve?</h3>
The curve is given as:
from x = 3 to x = 6
Start by differentiating the curve function
Evaluate
The length of the curve is calculated using:
This gives
![L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx](https://tex.z-dn.net/?f=L%20%3D%5Cint%5Climits%5E6_3%20%7B%5Csqrt%7B1%20%2B%20%5Bx%289x%5E2%20%2B%206%29%5E%5Cfrac%2012%5D%5E2%7D%5C%20dx)
Expand
This gives
Express as a perfect square
Evaluate the exponent
Differentiate
Expand
L = (6³ + 6) - (3³ + 3)
Evaluate
L = 192
Hence, the length of the curve is 192 units
Read more about curve lengths at:
brainly.com/question/14015568
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Answer:
20.625 dollars or about 20.63 dollars
Step-by-step explanation:
33/8 = 4.125
4.125 times 5 = 20.625
It would be d because youing the point slope equation which is (y - y1) = m (x- x1) when distributing the point and the slope into the equation asl well as sinplifying youll get D. Y1 is the value of the y in the ordered pair and x1 is the x value of the ordered pair.
To graph a situation that would involve a linear graph, first determine your x and y axes.
The x-axis will be the independent variable, one that does not change based on other variables. An example is time.
The y-axis, the dependent variable, depends on the independent variable.
The model equation for a linear line is y = mx + b.
"m" is the slope, and the "b" is the y-intercept (where the graph crosses the x-axis at x=0).
For example, a situtation could be that Joe starts with $10 in his account and adds $5 every day to his account.
The x-axis is time in days.
The y-axis is amount of money in his account.
The slope, or rate of change is 5.
The y-intercept, the amount of money he has at x=0 (0 days) is $10.
The equation would be y = 5x + 10
To draw this, plot the y-intercept at (0, 10), and the next point would be 5 units up and one unit to the right because the slope is 5, or 5/1 (remember slope is rise over run: "rise" up 5 and "over" to the right 1).
X = 0 ; y = 5 / 2 ;
y = 0 ; x = -5 ;
The right answer is C Z ;
