The amount Jerry paid in interest is $1,040.
Given to us,
Jerry's principal amount = $ 22,000,
quarterly payment for each quarter = $ 640
Total time for which Jerry paid each quarter = 9 years
As We know that in a year there are 4 quarters,
so, 
,
,
9 years = 36 quarters,
The total amount paid by Jerry for nine years in each quarter =
quarterly payment for each quarter x no. of quarters for which amount paid
Thus, the total amount paid by Jerry for nine years in each quarter is $23,040.
Therefore,
,
Hence, the amount Jerry paid in interest is $1,040.
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Answer:
29
Step-by-step explanation:
2 raise to power nine is the answer.
Cost = (3500 W)·(1 kw/1000 W)·(10 hrs/day)·(30 day/month)·($0.13/kw-hr)
Cost = (3500·1·10·30·0.13 / 1000)·(W·kW·hr·da·$ / W·da·month·kw·hr)
Cost = <em> 136.50 $/month</em>
The equation of line T is 2x - y = 7 ⇒ (6x - 3y = 21)
Step-by-step explanation:
A dilation is a transformation that produces an image that is the same shape as the original, but is a different size
- If the equation of a line is ax + by = k is dilated, with center origin and scale factor k, then the equation of the image of the line is kax + kby = kc
- The line and its image are parallel
- The coordinates of a general point on the image is (kx , ky)
Line L is mapped onto the line T by a dilation centered at the origin and a scale factor of 3.
That means lint T is the image of line L after dilation
∵ The equation of line L is 2x - y = 7
∵ Line L is dilated by scale factor 3 and centered at origin
- That means multiply the equation of line L by 3 to find the
equation of line t
∵ Line T is the image of line L after dilation
∴ The equation of line T is (3)(2x) - (3)(y) = (3)(7)
∴ The equation of line T is 6x - 3y = 21
<em>Very important note:</em>
The equation of line T is the same with equation of line L but multiplied by the scale factor 3 ⇒ L and T are coincide lines (same line)
That means the equation of lines T and L is 2x - y = 7
The equation of line T is 2x - y = 7 ⇒ (6x - 3y = 21)
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