Hope this helps and please give brainlist
There is no choice on your list that must represent an odd integer.
If 'z' is an even integer, then (z-1) and (z+1) must both be odd integers.
For this you would do

Because 60% is the same as 0.60. And solving a problem like this is the opposite of finding a percent of a number. When you solve this you get 80. So there are 80 students in total.
Answer: 5 to the 3rd times 3 to the second times 2
Step-by-step explanation: