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4 years ago

If p(x) = x2 – 1 and q (x) = 5 (x minus 1), which expression is equivalent to (p – q)(x)?

Mathematics

2 answers:

svlad2 [7]4 years ago

8 0

Answer:

c. (x^2-1)-5(x-1)

Step-by-step explanation:

on edge 2020 !

irakobra [83]4 years ago

5 0

Answer:

Step-by-step explanation:

p(x) = x^2 - 1

q(x) = 5(x - 1)

(p - q)(x) = x^2 - 1 - 5(x - 1)

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3 years ago

a cone has a circular base with a diameter of 18 inches. the height of the cone is 40 inches what is the approximate lateral are

lana66690 [7]

Lateral Area of cone=1130.4 inches^2

Step-by-step explanation:

Diameter of circular base = 18 inches

Height of cone = 40 inches

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The formula used to find Lateral Area of cone is:

$Lateral\,\,Area\,\.of\,\,cone=\pi rh$

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$Lateral\,\,Area\,\,of\,\,cone=\pi rh\\Lateral\,\,Area\,\,of\,\,cone=\pi *9*40\\Lateral\,\,Area\,\,of\,\,cone=1130.4 inches^2$

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3 years ago

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alisha [4.7K]

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the answer will be verified by an expert. Until then, talk to a tutor.

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2 years ago

The probability is 51% that the sample mean will be between what two values, symmetrically distributed around the population

Alisiya [41]

Answer:

The lower bound is, $-z=-0.69$ and the upper bound is $z=0.69$ .

Step-by-step explanation:

Let the random variable X follows a normal distribution with mean μ and standard deviation σ.

The the random variable Z, defined as $Z=\frac{X-\mu}{\sigma}$ is standardized random variable also known as a standard normal random variable. The random variable $Z\sim N(0, 1)$ .

The standard normal random variable has a symmetric distribution.

It is provided that $P(-z\leq Z\leq z)=0.51$ .

Determine the upper and lower bound as follows:

$P(-z\leq Z\leq z)=0.51\\P(Z\leq z)-P(Z\leq -z)=0.51\\P(Z\leq z)-[1-P(Z\leq z)]=0.51\\2P(Z\leq z)-1=0.51\\2P(Z\leq z)=1.51\\P(Z\leq z)=0.755$

Use a standard normal table to determine the value of z.

The value of z such that P (Z ≤ z) = 0.755 is 0.69.

The lower bound is, $-z=-0.69$ and the upper bound is $z=0.69$ .

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3 years ago