Ask question

Ask question

All categories

4 years ago

13

What is the chance of rolling five or more on a 12 sided die

1 answer:

Iteru [2.4K]4 years ago

6 0

Answer:

8/12 or 66.6%

Step-by-step explanation:

If we have 12 sides to a die then there are 12 possible outcomes, as a result if the dice would have a total of 8 sides that is either 5 or more (5,6,7,8,9,10,11,12,) that means 8/12 of the dice would be a satisfy the outcome we are looking for and 8/12 is around 67%

You might be interested in

I need help finding each measure in rhombus

3241004551 [841]

Rhombuses have acute and obtuse angles, so if it gives one just subtract it from 180

5 0

4 years ago

Given MN= PQ, NO=QR,.and OM=RP

shtirl [24]

Answer:

Step-by-step explanation:

4 0

3 years ago

Y=1/2×-6 ×=-4 what is the solution to the system of equations

hodyreva [135]

Answer:

(-4, -8)

Step-by-step explanation:

Use the substitution method. x = -4, so y = (1/2)x - 6 becomes:

y = (1/2)(-4) - 6, or y = -2 - 6, or y = -8.

The solution is (-4, -8).

8 0

3 years ago

Joe drove 345 miles on 25 gallons of gas What was his average miles per gallon?

hichkok12 [17]

Answer:

13.8 miles a gallon

Step-by-step explanation:

I think this because 345 divided by 25 equals 13.8 which would mean 13.8 miles for every gallon

7 0

3 years ago

Read 2 more answers

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago