Answer:
0.1
Step-by-step explanation:
73/844=0.08649=0.1(After rounding)
Answer:
ok
Step-by-step explanation:
i will ggfxhn. bjgxx
Answer:
Step-by-step explanation:
EXAMPLE #1:
What number is 75% of 4? (or Find 75% of 4.)
The PERCENT always goes over 100.
(It's a part of the whole 100%.)
4 appears with the word of:
It's the WHOLE and goes on the bottom.
A proportion showing one fraction with PART as the numerator and 4 as the denominator equal to another fraction with 75 as the numerator and 100 as the denominator.
We're trying to find the missing PART (on the top).
In a proportion the cross-products are equal: So 4 times 75 is equal to 100 times the PART.
The missing PART equals 4 times 75 divided by 100.
(Multiply the two opposite corners with numbers; then divide by the other number.)
4 times 75 = 100 times the part
300 = 100 times the part
300/100 = 100/100 times the part
3 = the part
A proportion showing the denominator, 4, times the diagonally opposite 75; divided by 100.
Answer:
37/8 (fraction) or 4.625 (decimal) or 4 5/8 (mixed number)
Step-by-step explanation:
115.2 pounds of type A coffee were used.
<h3>What is the solution of the equation?</h3>
A mathematical statement that has an "equal to" symbol between two expressions with equal values is called an equation.
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides. We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value of an unknown variable that represents an unknown quantity, equations can be solved.
Let the number of pounds of type A coffee be x and the number of pounds of Type B coffee be y.
According to the question, the equations are,
5.50x + 4.40y = 762.30
x = 4y
So, the solution of the equation is obtained as follows:
5.50(4y) + 4.40y = 762.30
26.40y = 762.30
y = 762.30/26.40
y = 28.8 pounds
x = 4*28.8 = 115.2 pounds
Learn more about equations here:
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