How many moles of hcl are present in 0.70 l of a 0.33 m hcl solution? (molar mass of hcl = 36.46 g/mol?
1 answer:
V=0.7 l
c=0.33 moles/l
n(HCl)=v·c
n(HCl) = 0.7 l · 0.33 moles/l = 0.231 moles
0.231 moles of HCl are present
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