In this case, according to the given information in the problem, it turns out possible for us to calculate the specific gravity of this alcohol by simply dividing its density, 0.79 g/mL by that of the water, 1 g/mL just as a reference for us to work with:
Thus, we plug in the densities to obtain:
Which is dimensionless as g/mL is cancelled out due to its presence on both top and bottom of the previous formula.