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2 years ago

19 1/2 divided by 3/4

Mathematics

2 answers:

NNADVOKAT [17]2 years ago

7 0

The answer is 26 you can make it an improper fraction.

liberstina [14]2 years ago

4 0

19 1/2 divided by 3/4 is 26

Hope this helps!
Let me know! :)

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A cereal box is 8 in by 2in by 12in what is the surface area.

LUCKY_DIMON [66]

192 in2

The formula for surface area is 2(lw + wh + hl) = 2(2*8 + 12*8 + 12*2) = 2(16+56+24) = 2(96) = 192

4 0

3 years ago

On a cold January morning, the radiator fluid in Christine’s truck is –13°F. With the engine on, the temperature goes up by 3.6°

faust18 [17]

Answer:

It will take 17.5 minutes to reach 50 degrees F.

Step-by-step explanation:

Current temperature = -13 degrees F

With the engine on, the temperature goes up by 3.6°F per minute.

Let us assume that it takes x minutes to reach 50 degrees F.

So, the time taken will be =

$-13+3.6(x)=50$

=> $3.6x=50+13$

=> $3.6x=63$

x = 17.5 minutes

The expression that tells how much the temperature needs to change from -13°F to 50°F is : $-13+3.6(x)=50$

It will take 17.5 minutes to reach 50 degrees F.

5 0

3 years ago

Read 2 more answers

Write the inequality shown in this graph.

kykrilka [37]

Answer:

y > -1/2 x + 4

Step-by-step explanation:

Equation of a line : (y-y1)/(y2-y1) = (x-x1)/(x2-x1)

(y-4)/(2-4)= (x-0)/(4-0)

(y-4)/-2 = x/4

(-y+4)/2 = x/4

-y+4 = 1/2 x

-y = 1/2 x - 4

y = -1/2 x + 4

the solutions of the inequality are the points above this line, so

y > -1/2 x + 4

8 0

2 years ago

What is the answer to 4n-2n=4

artcher [175]

Answer: n=2

Step-by-step explanation: 4n-2n=4

4(2)-2(2)=

8-4=4

5 0

3 years ago

Read 2 more answers

The diagram shows a square ABCD with sides of length 20cm. it also shows a semi circle and an arc circle AB is the diameter of t

Brut [27]

Answer:

Area of Shaded Region $=50\pi$ cm^2$

Area of Semicircle $=50\pi$ cm^2$

$\dfrac{\text{Area of Shaded region}}{\text{Area of Square}}=\dfrac{ \pi}{8}$

Step-by-step explanation:

Area of Shaded Region = Area of Sector - Area of Semicircle

<u>Area of Sector</u>

Radius of the sector =20cm

$=\frac{90}{360}X\pi *20^2\\ =100\pi cm^2$

<u>Area of Semicircle</u>

Since AB is the diameter of the semicircle

Radius of the Semicircle=20/2=10cm

Area of semicircle

$=\frac{\pi r^2}{2}\\ =\frac{\pi *10^2}{2}\\=50\pi cm^2$

Therefore, area of Shaded Region

$=100\pi -50 \pi\\=50\pi$ cm^2$

Area of Square =20 X 20 $=400 cm^2$

$\dfrac{\text{Area of Shaded region}}{\text{Area of Square}} \\=\dfrac{50 \pi}{400} \\=\dfrac{ \pi}{8}$

4 0

3 years ago