Please help need answer asp

Lostsunrise [7]

Jayne will need to drive 40 mph on the way back.

4 0

2 years ago

Suppose that in a random sample of 300 employed Americans, there are 57 individuals who say that they would fire their boss if t

otez555 [7]

Answer:

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 300, \pi = \frac{57}{300} = 0.19$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 - 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.1456$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 + 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.2344$

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

4 0

2 years ago

What is the solution for r in the following system of equations? 2x + 3y = 16 2 + 2y = 10

klio [65]

Answer:

(2,4)

*View attached graph*

Step-by-step explanation:

2x + 3y = 16

2 + 2y = 10

-2 - 2

2y = 8

/2 /2

y = 4

2x + 3y = 16

2x + 3(4) = 16

2x + 12 = 16

- 12 - 12

2x = 4

/2 /2

x = 2

(x,y) -> (2,4)

Hope this helps!

8 0

2 years ago

A bag contains 10 red marbles and 15 green marbles.If yuki selects a marble from the bag without looking, what is the probabilit

Grace [21]

Incomplete Question (See Complete Question Below)

A bag contains 10 red marbles and 15 green marbles.If Yuki selects a marble from the bag without looking, what is the probability that she will pull a red marble?

A-1/5

B-2/5

C-1/2

Answer:

The probability of pulling a red marble is $\frac{2}{5}$

Step-by-step explanation:

Given

Red Marble = 10

Green Marble = 15

Required

The probability of picking a red marble

First, the total number of marble has to be calculated

Total = Red Marble + Green Marble

Total = 10 marbles + 15 marbles

Total = 25 marbles

The probability of an event is often calculated by dividing the number of required outcomes by the number of possible outcomes.

In this case, the probability of pulling a red marble is calculated as follows:

$P(R) = \frac{n(R)}{T}$

Where P(R) represents probability of pulling a red marble

n(R) represents number of red marbles

n(R) = 10

T represents total number of marbles

T = 25

By substitution,

$P(R) = \frac{n(R)}{T}$ becomes

$P(R) = \frac{10}{25}$

Reduce fraction to lowest term by dividing the numerator and denominator by 5

$P(R) = \frac{2}{5}$

Hence, the probability of pulling a red marble is $\frac{2}{5}$

7 0

2 years ago

Solve (t - 3)2 = 6. The arrow is at a height of 48 ft after approximately _ s and after _s

Slav-nsk [51]

Answer:

The arrow is at a height of 48 ft after approximately 0.55 s and after 5.45 s

Step-by-step explanation:

The following information is missing:

The height of an arrow shot upward can be given by the formula s = v0*t - 16*t², where v0 is the initial velocity and t is time.How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s?

If the arrow is at a height of 48 ft and its initial velocity is 96 ft/s, then:

48 = 96*t - 16*t²

16*t² - 96*t + 48 = 0

16*(t² - 6*t + 3) = 0

t² - 6*t + 3 = 0

t² - 6*t + 3 + 6 = 0 + 6

t² - 6*t + 9 = 6

(t - 3)² = 6

t - 3 = √6

t - 3 = 2.45; t = 2.45 + 3; t = 5.45

or

t - 3 = -2.45; t = -2.45 + 3; t = 0.55

3 0

3 years ago

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