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Natali [406]
3 years ago
15

How do you solve 3X+2y=9,for y

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer and Explanation:

<em>Solving 3x + 2y = 9 for y gives y = -(3/2)x + (9/2). </em>

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[1 6 9 3]<br> [2 5 8 1] <br> [0 2 2 4] <br> what are the dimensions of the matrix
nasty-shy [4]

Answer:

4 by 3

Explanation:

Rows by columns

5 0
2 years ago
What is the reflection image of P (0, 0) after two reflections, first across x = −3 and then across y = −3? (−6, −6) (−6, −3) (−
Nadya [2.5K]

Answer:

(-3,-3)

Step-by-step explanation:

If we reflect P (0,0) across x=-3 and then across y=-3, then the new point of P would be (0-3,0-3)=(-3,-3)

4 0
3 years ago
Fourth-eight is what percent of 60
dsp73
48 is 80% of 60

48 of 60 can be written as 48/60

Multiply both the numerator and the denominator by 100
48/60 · 100/100 = 80/100 = .8 = 80%

If you are using a calculator, simply enter 48 ÷ 60 · 100 which will give you 80 as the answer. 




6 0
3 years ago
Read 2 more answers
In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th
ehidna [41]

Question:

In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th birthday, 25% married by their 20th birthday, and 76% married by their 30th birthday. Based on these data, what is the probability that in a family with two daughters, the first and second daughter will be married by the following ages? (Enter your answers to four decimal places.) (a) 18 years of age (b) 20 years of age (c) 30 years of age

Answer:

A.) 0.0064

B.) 0.0625

C.) 0.5776

Step-by-step explanation:

Given the following :

Married by 18th birthday = 8% = 0.08

Married by 20th birthday = 25% = 0.25

Married by 30th birthday = 76% = 0.76

In a family with two(2) daughters :

P(First daughter will be married by 18) = 0.08

P(second daughter will be married by 18) = 0.08

P(1st and 2nd married by 18) = (0.08×0.08) = 0.0064

B.)

P(First daughter will be married by 20) = 0.25

P(second daughter will be married by 20) = 0.25

P(1st and 2nd married by 20) = (0.25×0.25) = 0.0625

C.)

P(First daughter will be married by 30) = 0.76

P(second daughter will be married by 30) = 0.76

P(1st and 2nd married by 30) = (0.76×0.76) = 0.5776

6 0
2 years ago
Step 1: d+3 &lt; 1 <br><br> Step 2: b+6&lt; 9
In-s [12.5K]

Answer:

1) d < -2

2) b < 3

Step-by-step explanation:

1) d+3< 1

subtract both sides by 3

d+3 -3 < 1-3

d<-2

2) b+6< 9

subtract both sides by 6

b+6 -6 < 9 -6

b< 3

3 0
2 years ago
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