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Paha777 [63]
3 years ago
12

I need help to answer my word problem

Mathematics
1 answer:
Makovka662 [10]3 years ago
3 0

Answer:

What’s the question?

Step-by-step explanation:

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Help just help me... please
mr Goodwill [35]

Answer:

Its going by 3/8.

Step-by-step explanation:

the missing number is 1 5/8. I don't know if I'm right for the second

5 0
3 years ago
Given that sec (x) = 2 and cosec (x) is negative,
weeeeeb [17]

Answer:

i) sin(2x) = -\frac{\sqrt{3}}{2}

ii) cot(x+360) = -\frac{\sqrt{3}}{3}

iii) sin(x-180) = \frac{\sqrt{3}}{2}

Step-by-step explanation:

sec(x) = 2

Since cos(x) is reciprocal of sec(x), this means:

cos(x) = \frac{1}{2}

cosec(x) is negative , this means sin(x) is also negative. The only quadrant where cos(x), sec(x) are positive and sin(x), cosec(x) are negative is the 4th quadrant. Hence the terminal arm of the angle x is in 4th quadrant.

Part i)

sin(2x) can be simplified as:

sin(2x) = 2 sin(x) cos(x)

First we need to find the value of sin(x). According to Pythagorean identity:

sin^{2}(x)=1-cos^{2}(x)\\\\ sin(x)=\pm \sqrt{1-cos^{2}(x)}

Since, angle is in 4th quadrant, sin(x) will be negative. So considering the negative value of sin(x) and substituting the value of cos(x), we get:

sin(x)=- \sqrt{1-cos^{2}(x)}\\\\ sin(x)=-\sqrt{1-(\frac{1}{2})^{2}}\\\\ sin(x)=-\frac{\sqrt{3}}{2}

So,

sin(2x)=2 \times -\frac{\sqrt{3} }{2} \times \frac{1}{2}\\\\ sin(2x)=-\frac{\sqrt{3}}{2}

Part ii)

We have to find cot(x + 360)

An addition of 360 degrees to the angle brings it back to the same terminal point. So the trigonometric ratios of the original angle and new angle after adding 360 or any multiple of 360 stay the same. i.e.

cot(x + 360) = cot(x)

cot(x) = \frac{cos(x)}{sin(x)}\\

Using the values, we get:

cot(x)=\frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2} }\\\\ cot(x)=-\frac{\sqrt{3}}{3}

Part iii)

We need to find the value of sin(x - 180)

sin(x - 180) = - sin(x)

Addition or subtraction of 180 degrees changes the angle by 2 quadrants. The sign of sin(x) becomes opposite if the angle jumps by 2 quadrants. For example, sin(x) is positive in 1st quadrant and negative in 3rd quadrant.

So,

sin(x - 180) = -(-\frac{\sqrt{3}}{2}) = \frac{\sqrt{3}}{2}

6 0
3 years ago
A school earns $70 from selling 50 tickets for the school play each ticket costs the same price how much does the school earn fo
Georgia [21]
The answer is that the school is going to earn $1.40 for each ticket so thats the answer: $1.40
6 0
3 years ago
Solve for q 19 = q + 4 q=
larisa86 [58]

Answer:

Assuming the 19 stood for an exponent, q = 1.098...

Step-by-step explanation:

Plugging in q^{19} = q + 4 in the graphical calculator, we can see that the solution is approximately q=1.098. There are no ways of solving this equation algebraically.

7 0
3 years ago
Read 2 more answers
Six pyramids are shown inside of a cube. The height of the cube is h units. Six identical square pyramids can fill the same volu
MAXImum [283]

Answer:

(A)The height of each pyramid is One-half h units.

Step-by-step explanation:

Height of the Cube = h units

Volume of the Cube =h^3 $ cubic units

If Base of the cube =Base of the square pyramid

Base of the square pyramid = h units

\text{Volume of a Pyramid}=\dfrac{1}{3}*Base Area*Height

\text{Volume of One Pyramid}=\dfrac{1}{3}*h^2*Height

\text{Volume of Six Pyramids}=6*\dfrac{1}{3}*h^2*Height\\=(2h^2*Height)\:cubic\:units

Since Volume of the Cube = Volume of Six Square Pyramids

Then:

2h^2*Height=h^3\\Height=\dfrac{h^3}{2h^2} \\$Height of each pyramid =\dfrac{1}{2}h \:Units

5 0
4 years ago
Read 2 more answers
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