Based only on the information given in the diagram, which congruence theorems

Mathematics

2 answers:

lisabon 2012 [21]2 years ago

8 0

Answer: ASA, LA, LL, and SAS

Step-by-step explanation:

Finger [1]2 years ago

3 0

Answer: A) SAS and B) ASA and (D) LA

Step-by-step explanation:

A) AC = XZ Sides are congruent

∠C = ∠Z Angles are congruent

BC = YZ Sides are congruent

Side-Angle-Side

B) ∠A = ∠X Angles are congruent

AC = XZ Sides are congruent

∠C = ∠Z Angles are congruent

Angle-Side-Angle

C) AB = XY is not given. We can use Pythagorean Theorem to discover that they are the same but since it is not given we cannot use Side-Side-Side.

D) AC = XZ Legs are congruent

∠A = ∠X acute Angles are congruent

Leg-Angle

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A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form

Over [174]

Answer:

$\vec{v}= \text{ or } \approx$

Step-by-step explanation:

Component form of a vector is given by $\vec{v}=$ , where $i$ represents change in x-value and $j$ represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector $\vec{v}=$ , the magnitude is $||v||=\sqrt{i^2+j^2$ .

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being $i$ , one leg being $j$ , and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

$\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}$

To find the other leg, $i$ , we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

$\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}$