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Anna [14]
3 years ago
13

A company determines that its marginal​ cost, in​ dollars, for producing x units of a product is given by Upper C prime (x )equa

ls4500 x Superscript negative 1.9​, where xgreater than or equals1.11. Suppose that it were possible for the company to make infinitely many units of this product. What would the total cost be?
Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

Total Cost = Fixed Cost as x --> ∞

Step-by-step explanation:

C'(x) = 4500 x⁻¹•⁹ where x ≥ 1

Marginal Cost = C'(x) = (dC/dx)

C(x) = ∫ (marginal cost) dx

C(x) = ∫ (4500 x⁻¹•⁹)

C(x) = (-5000 x⁻⁰•⁹) + k

where k = constant of integration or in economics term, K = Fixed Cost.

C(x) = [-5000/(x⁰•⁹)] + Fixed Cost

The company wants to make infinitely many units, that is, x --> ∞

C(x --> ∞) = [-5000/(∞⁰•⁹)] + Fixed Cost

(∞⁰•⁹) = ∞

C(x --> ∞) = [-5000/(∞)] + Fixed Cost

But mathematically, any number divide by infinity = 0;

(-5000/∞) = 0

C(x --> ∞) = 0 + Fixed Cost = Fixed Cost.

Total Cost of producing infinite number of units for this cost function is totally the Fixed Cost.

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A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver
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Answer:

The time of a commercial airplane is 280 minutes

Step-by-step explanation:

Let

x -----> the speed of a commercial airplane

y ----> the speed of a jet plane

t -----> the time that a jet airplane takes  from Vancouver to Regina

we know that

The speed is equal to divide the distance by the time

y=2x ----> equation A

<u><em>The speed of a commercial airplane is equal to</em></u>

x=1,730/(t+140) ----> equation B

<u><em>The speed of a jet airplane is equal to</em></u>

y=1,730/t -----> equation C

substitute equation B and equation C in equation A

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Solve for t

1/t=(2/(t+140))

t+140=2t

2t-t=140

t=140 minutes

therefore

The time of a commercial airplane is

t+140=140+140=280 minutes

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