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yuradex [85]
2 years ago
13

The sum of the squares of two consecutive odd positive integers is 130. find the integers

Mathematics
1 answer:
VladimirAG [237]2 years ago
8 0
2 consecutive odd positive integers....x and x + 2

x^2 + (x + 2)^2 = 130
x^2 + (x + 2)(x + 2) = 130
x^2 + x^2 + 4x + 4 = 130
2x^2 + 4x + 4 = 130
2x^2 + 4x + 4 - 130 = 0
2x^2 + 4x - 126 = 0
2(x^2 + 2x - 63) = 0
2(x - 7)(x + 9) = 0

x - 7 = 0
x = 7

x + 9 = 0
x = -9 (cant be this one because it is negative

so x = 7...and x + 2 = 7 + 2 = 9......ur 2 numbers are 7 and 9

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tino4ka555 [31]

Answer:

-32

Step-by-step explanation:

Simply input the x and y values.

New equation:

| 147-(-9) | /(-4) +7

Step one:

<em>147-(-9)   = 156</em>

<em>Step two:</em>

|156|/-4    =-39

Step three:

-39+7      =-32

If you evaluate the expression it comes out to -32

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3 0
2 years ago
In the parallelogram DEFG, DH=x+1, HF=3y, GH=3x-4, and HE=5y+1. Find the values of x and y. The diagram is not drawn to scale.
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Answer:

Step-by-step explanation:

Given:  In parallelogram DEFG,

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Solution: Since, DH,HF, GH and HE represents the diagonals of the parallelogram and we know that the diagonals of the parallelogram bisect each other, therefore

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3x-4=5y+1      (2)

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