4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2
5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3
6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1
76.91 = C
cos(77)= (17-3)/ C
X^2=256
x=±√256
x=±16
x=-16 and 16
A) because a kite has two pair of equal sides
The left and right bound limits of the function approach positive infinity, so the limit of this function as x approaches 2 is infinity.
