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Sauron [17]
4 years ago
15

If two opposite sides of a square are increased by 15 meters and the other sides are decreased by 5 meters, the area of the rect

angle that is formed is 69 square meters. find the area of the original square.
Mathematics
1 answer:
ZanzabumX [31]4 years ago
4 0
<span>Let y= original side So A = LW 60 = (y+15)(y-13) (y+15)(y-13) = 60 y^2 + 2y - 195 = 60 y^2 + 2y- 195 - 60 = 0 y = -17 or y= 15 Toss out the negative solution to get y= 15 as the only solution. So the square has a side length of 15 meters. The area of this square is 15^2 = 15*15 = 225 square meters.</span>
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Answer:

1 3/4 miles

Step-by-step explanation:

add 3/4 +3/4+1/4 to get your answer

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y=\dfrac{1}{3}x-3\\\\for\ x=0\to y=\dfrac{1}{3}(0)-3=-3\to(0,\ -3)\\\\for\ x=3\to y=\dfrac{1}{3}(3)-3=1-3=-2\to(3,\ -2)\\\\y=-3x-3\\\\for\ x=0\to y=-3(0)-3=-3\to(0,\ -3)\\\\for\ x=-1\to y=-3(-1)-3=3-3=0\to(-1,\ 0)

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solid line. we shade above the line

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the dotted line. shadow above the line

Answer in the attachment (the first graph).

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3 years ago
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7 0
3 years ago
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Find the term of 7 10 13 which is 46.
Dennis_Churaev [7]
46 = (7*4) +(10/2) +13
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so than i ve understood it right your exercise 
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Lucy spent a total of $6.60 on 5 apples and a package of grapes. If the package of grapes cost $2.35, how much did each apple co
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<h2>MARK ME AS BRAINLIST</h2><h3>PLZ FOLLOW ME</h3>

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