Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.
The length of the poster in its frame is ...
(frame width on one side) + (poster length) + (frame width on the other side)
2 in + 32 in + 2 in = 36 in
Likewise, the width of the poster in its frame is ...
2 in + 24 in + 2 in = 28 in
The area of a rectangle 36 in by 28 in is the product of these dimensions:
Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
First answer is 4 chances and second answer is 2 chances
Answer:
B. a = 4, b = -8, c = -3
Step-by-step explanation:
The quadratic equation given is:
The general form of a quadratic equation is given as:
Let us put the given equation in this form and then compare with the general form of the quadratic equation.
Therefore, by comparing:
a = 4
b = -8
c = -3
The correct option is B
Answer:
C..... I think it is a answer
Answer: x = 1, y = - 5
Step-by-step explanation:
The given system of linear equations is expressed as
x - 2y = 11- - - - - - - - - - - - -1
- x + 6y = - 31- - - - - - - - - - - -2
We would eliminate x by adding equation 1 to equation 2. It becomes
- 2y + 6y = 11 - 31
4y = - 20
Dividing the the left hand side and the right hand side of the equation by 4, it becomes
4y/4 = - 20/4
y = - 5
Substituting y = - 5 into equation 1, it becomes
x - 2 × - 5 = 11
x + 10 = 11
Subtracting 10 from the left hand side and the right hand side of the equation, it becomes
x + 10 - 10 = 11 - 10
x = 1
