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Blababa [14]
2 years ago
13

6 x + = 0 what is x??

Mathematics
1 answer:
lapo4ka [179]2 years ago
4 0

Answer:

Here are some answers

1. If you meant 6x = 0 then your answer is 0

2. If you meant 6 + x = 0 then your answer is -6

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PLEASE PEOPLE , I NEED HELP CAN YOU HELP ME PLEASE :,)
Tasya [4]

Step-by-step explanation:

= (1 + 5z)(-4)

= (1 + 5z) × (-4)

= 1.(-4) + 5z. (-4)

= -4 - 20z

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2 years ago
PLEASE HELP WITH ALL QUESTIONS WILL GIVE BRAINLIEST AND WILL GIVE 33 POINTS
MrMuchimi

uh where the question?

6 0
3 years ago
The hypothesis was that all three segments of the regulatory region are required for highest expression of the Hoxd13 gene. Is t
Mama L [17]

Answer:

Yes, it is.

Step-by-step explanation:

The hypothesis made on the Hoxd13 gene expression justified the results obtained. This is because if one of the three segments is removed, the value of the expression level will be reduced to approximately below 100% of the control. Therefore, it can be inferred that the theoretical analysis justified the results obtained.

6 0
3 years ago
The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y
Lelechka [254]

Given the next quadratic function:

y=2x^2+3x-2

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

x_V=\frac{-b}{2a}

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

\begin{gathered} x_V=\frac{-3}{2\cdot2} \\ x_V=-\frac{3}{4}=-0.75 \end{gathered}

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:

6 0
1 year ago
Remer<br> 1) 5k? + 10k + 6 = 0
IceJOKER [234]

Ignoring the "?" in your question:

5k+10k+6=0 \iff 15k+6=0 \iff k=-\dfrac{6}{15}

If the "?" is a squared symbol that wasn't caught:

5k^2+10k+6=0

Use the quadratic formula

x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

to get the solutions:

x_{1,2}=\dfrac{-10\pm\sqrt{100-120}}{10}

as you can see, the discriminant is negative, so the equation has no solution.

6 0
3 years ago
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