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Karolina [17]
3 years ago
12

Please show me how you got the answer. thank you in advance.

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
5 0
Write an equation system based on the problem
We can write the equation for "Twice the price in Japan minus five times the price in India is $20.60" as
∴ 2j - 5i = 20.6  <em>(first equation)</em>
We can write the equation for "Thirty cents less than three times the lowest price is thirty cents" as
∴ 3i - 0.30 = 0.30  <em>(second equation)</em>

Solve the equations
First, solve the second equation to find the price in India
3i - 0.3 = 0.3
3i = 0.3 + 0.3
3i = 0.6
  i = 0.6/3
  i = 0.2

Second, solve the first equation by subtitution of the value of i to the equation
2j - 5i = 20.6
2j - 5(0.2) = 20.6
2j - 1 = 20.6
2j = 20.6 + 1
2j = 21.6
  j = 21.6/2
  j = 10.8

The price in India is $0.20 and the price in Japan is $10.80
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Please help me solve this problem!!!
Hatshy [7]

Answer:

w = 9

Step-by-step explanation:

We can use ratios to solve

2        3

---- = ------

6         w

Using cross products

2w = 3*6

2w = 18

Divide by 2

w = 9

4 0
4 years ago
A trapezoid has an area of 342 square yards. The length of one base is 17 yards, and the length of the other base is 21 yards. W
dedylja [7]

The height of trapezoid is 18 yards

<em><u>Solution:</u></em>

Given that, trapezoid has an area of 342 square yards

The length of one base is 17 yards, and the length of the other base is 21 yards

To find: height of trapezoid

<em><u>The area of trapezoid is given by formula:</u></em>

area = \frac{a+b}{2} \times h

Where "h" is the height

"a" and "b" are the length of base

Here given that,

area = 342 square yards

a = 17 yards

b = 21 yards

h = ?

<em><u>Substituting the values we get</u></em>,

342 = \frac{17+21}{2} \times h\\\\342 \times 2 = 38 \times h\\\\ 684 = 38h\\\\h = \frac{684}{38}\\\\h = 18

Thus height of trapezoid is 18 yards

6 0
3 years ago
How do i do this???????
Fittoniya [83]

Answer:

2y-4-6y-12=4

-4y=20

y= -5

Step-by-step explanation:

because (y+2)(y-2)=y^2-4

so we have the step to let the every part have the same denominator y^2-4

2(y-2)/(y+2)(y-2)  -6(y+2)/(y-2)(y+2)=4/(y-2)(y+2)

the denominators are the same so the equality .we just need the part over be the same 2y-4-6y-12=4

y= -5

3 0
3 years ago
Prepare a ledger using the three-column form of account. Enter the trial balance amounts into the balance column and then post t
GREYUIT [131]

Answer:

Insurance Expense (Dr.) $200

Prepaid Insurance (Cr.) $200

Supplies expense (Dr.) $1,250

Cash (Cr.) $1,250

Depreciation Expense (Dr.) $424

Accumulated depreciation Building (Cr.) $304

Accumulated Depreciation Equipment (Cr.) $120

Interest Expense (Dr.) $200

Interest Payable (Cr.) $200

Unearned Rent Revenue (Dr.) $2,200

Rent Revenue (Cr.) $2,200

Salaries Expense (Dr.) $700

Salaries Payable (Cr.) $700

Step-by-step explanation:

Three column ledger has particular, debit and credit columns in which all the entries which are recorded in journal entries are posted to have a clear view of the expense and income.

3 0
3 years ago
2
jolli1 [7]

Answer:

E = 30 \times H

$570

Step-by-step explanation:

Given that:

For each hour of tutoring, Lena earns 30 dollars.

E is her earning and

H is the number of hours for which she tutors.

To find:

Equation relating E to H.

Solution:

Let Lena tutors for 1 hour, then the earning = 30 dollars

Let Lena tutors for 2 hours, then the earning = 30+30 OR 2\times30 = 60 dollars

Let Lena tutors for 3 hours, then the earning = 30+30 +30 OR 3\times30 = 90 dollars

If Lena tutors for H number of hours, then the earning, E = 30 + 30 + .... + 30 (H times) i.e.

E = 30 \times H

So, the equation that relates E to H is given as:

E = 30 \times H

Now, it is given that she tutors for 19 hours.

Let us put H = 19 hours in the above equation:

E = 30 \times 19 \\\Rightarrow E = \$570

Therefore, the earning for 19 hours of tutoring is <em>570 Dollars.</em>

4 0
4 years ago
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