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katrin [286]
2 years ago
12

My parents recently moved to the Poconos, they got 30 or more inches of

Mathematics
1 answer:
jekas [21]2 years ago
7 0

Answer:

25ft

Step-by-step explanation:

2hr=10ft

5hr=25ft

5-2=3 so you have to find what they did for the 3 hours which is another 2 plus half so 25ft.

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Find the distance between 6.2 and<br> -4.3 on a number line.
Nitella [24]

Answer:

The two given numbers are 10.5 units apart.

Step-by-step explanation:

Subtract the smaller from the larger.  The larger number here is 6.2. Then we have

6.2 - (-4.3) = 6.2 + 4.3 = 10.5

The two given numbers are 10.5 units apart.

8 0
3 years ago
Number 1 write in standard form correct answer will get brainliest
Fudgin [204]

Answer:

Step-by-step explanation:


5 0
3 years ago
Could you please help me for this question?
Olin [163]

Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

__

The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

__

The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

6 0
2 years ago
Vicki and Tamra are working on their math homework together. Vicki has worked p problems and Tamra has worked 3 times as many as
EleoNora [17]
P+3p=4p which is the answer
6 0
2 years ago
Read 2 more answers
Int he figure below find AC
Ahat [919]

Given :-

  • Two triangles with their two angles equal .

To Find :-

  • Measure of AC .

Answer :-

Here in ∆ABC and ∆EDC ,

  • \angle CAB = \angleCED (given )
  • \angle CBA = \angleCDE (given)

Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,

→ AC/EC = BC/DC

→ AC/9 = 8/12

→ AC = 8/12 * 9

→ AC = 6

<u>Hence</u><u> the</u><u> </u><u>measure</u><u> of</u><u> </u><u>side </u><u>AC </u><u>is </u><u>6</u><u> </u><u>.</u>

I hope this helps.

7 0
2 years ago
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