Quadrant: one of the four region into which the x and y axis separate the coordinate plane
Ordered pairs: a pair of numbers that are used to correspond to a pint on a graph where the first number is the x coordinate and the second is the y coordinate
Y-intercept: the point where a graph crosses the y-axis
Parallel lines: Lines that have the same slope and never intersect
Slope intercept form: A linear equation in the form y=mx+b where m is the slope and b is the y-intercept
Linear Equation: An equation with two variables that makes up a straight line on a coordinate plane
Answer:histogram 4
Is this for stats? each number is going by 5 and looking at the numbers you can easily eliminate 2 and 3 as there is nothing in the area of 50-60 that only leaves 1 and 4 look at the numbers and how they add up in the frequency from 70-75 there are two numbers that meet the criteria. Histogram 1 only shows one number for that section so i assume that it should be number 4.
Answer: Yes
Step-by-step explanation:
Step #1: Lacey has 2 3/4 yards of wrapping paper remaining. She has six boxes to wrap, each of which requires 3/8 of a yard of paper. First, you must find the total number of yards of wrapping paper needed for six boxes.
Number of boxes * Number of wrapping paper required for each box
6 x 3/8 = 9/4
Step #2: Subtract the number of yards of wrapping paper remaining by the total number of wrapping for 6 boxes.
2 3/4 - 9/4 = 1/2
Step #3: Determine and solve whether Lacey will have enough wrapping paper left to also wrap a book that requires 1/2 yard of paper. To solve, subtract the remaining amount of wrapping paper by the amount of wrapping required for a book.
1/2 - 1/2 = 0
So, yes Lacey will have just enough wrapping paper to also wrap a book that requires 1/2 yard of paper.
The outcomes of rolling fair six sided die is . The prime numbers in the above outcomes are . The probability of not rolling a prime number is .
Each trial is independent.
In the given experiment of 100 trials, the binomial probability model can be used to predict the number of occurrence of non-prime numbers (X). The probability mass function is
. Since
<span>(m^4+3m^3-26m^2-2m-24)÷(m-4)
step 1: m^4+3m^3+26m^2-2m-24
----------------------------------
m-4
step 2: m^4+4m^3+7m^3-28m^2+2m^2-8m+6m-24
----------------------------------------------------------
m-4
step 3: m^3 (m-4)+7m^2x(m-4)+2mx(m-4)+6(m-4)
---------------------------------------------------------
m-4
step 4: (m-4)x(m^3+7m^2+2m+6)
----------------------------------
m-4
step 5: (m-4)
</span><span><span> --------- cancelled out</span>
m-4
answer: m^3+7m^2+2m+6
</span>