6.95 to one decimal place would be 7 because if it was 6.9 then it would round to 7 and the 6.95 rounds the 9 to a 10 and you cant have 6.10 so it would be 7.

8 0

4 years ago

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The graph below shows a system of equations:

Nostrana [21]

3y = -2x + 2
y = x + 4 (Substitute the y)

3(x + 4) = -2x + 2 (Distribute)
3x + 12 = -2x + 2 (Add 3 to both sides)
+3x +3x
------------------------------------------
12 = 1x + 2 (Subtract 2 from both sides)
-2 - 2
------------------------
10 = 1x (Divide by 1 on both sides)
10/1 = 1x/1
x = 10
This is your x-coordinate

4 0

4 years ago

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Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant criteria?Tem

Xelga [282]

Answer:

B. No, this distribution does not appear to be normal

Step-by-step explanation:

Hello!

To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.

The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.

As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.

The answer is B.

I hope it helps!

3 0

3 years ago