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Karo-lina-s [1.5K]
3 years ago
13

Evaluate the following:(-8)2​

Mathematics
2 answers:
jek_recluse [69]3 years ago
6 0
You have to multiply. So your answer will be -16.
Zigmanuir [339]3 years ago
5 0

Answer:

<h3>-16</h3>

Step-by-step explanation:

PEMDAS- (Parenthesis, Exponents, Multiply, Divide, Add, and Subtract) from left to right.

BOMDAS- (Brackets, Of, Multiply, Divide, Add, and Subtract) from left to right.

(-8)2

-8*2 (First, remove parenthesis.)

-8*2=-16

-16

Therefore, the final answer is -16.

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Which equation represents a line which is perpendicular to the line y = 3x – 8?
svetoff [14.1K]
It’s wing and Mac and orange
7 0
3 years ago
Read 2 more answers
Using appreciate property -2/3 × 3/5 + 5/2 - 3/5 × 1/6 ​
o-na [289]

Answer:

The answer for your question is 2.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help it will help a lot i really need this!!
Lorico [155]

Answer:

A' = (0,0)

B'=(8,0)

C'=(8,2)

D'=(0,2)

It is not a rigid motion.

Step-by-step explanation:

To use the mapping rule, substitute the original x and y values in it.

The coordinates of A are (0,0).

Using the mapping rule, the x coordinate of A' = 2x0 = 0

Using the mapping rule, the y coordinate of A' = (1/2)x0=0

So A' will not change locations. The image will be at (0,0).

The coordinates of B are (4,0)

Using the mapping rule, the x-coordinate of B' = 2x4 = 8

Using the mapping rule, the y-coordinate of B' = (1/2)x0=0

Therefore the image of B' will be located at coorindate (8,0)

The coorindates of C are (4,4).

Using the mapping rule, the x-coordinate of C' = 2x4=8

Using the mapping rule, the y-coordinate of C' = (1/2)x4=2

Therefore the image of C' will be located at coordinate (8,2)

The coordinates of D are (0,4)

Using the mapping rule, the x-coordinate of D' = 2x0 = 0

Using the mapping rule, the y-coordinate of D' = (1/2)x4=2

Therefore the image of D' will be located at coordinate (0,2)

<em>Is the transformation a rigid motion?</em>

NO, this transformation is not a rigid motion because the relative distance between the points does not stay the same after they have been transformed. The transformation is not a translation , rotation, reflection, nor glide reflection.

6 0
3 years ago
P is the incenter of QRS. Use the given information to determine find the indicated measure.
never [62]
<span>The incenter is equidistant from all three triangle sides.
So, PJ = PK = PL.
PJ = 4x -8
PL = x + 7

Therefore,
</span>4x -8 = <span>x + 7
3x = 15
x = 5
So, PJ = 12
PL = 12 and
PK = 12

</span>
5 0
3 years ago
Triangle ABC is labeled with points A(5, 2), B(1, 2) and C(3, 6) on a coordinate plane. Find the coordinates of A' B' C' after a
Ilia_Sergeevich [38]

Answer:

After reflection over the x-axis, we have the coordinates as follows;

A’ (5,-2)

B’ ( 1,-2)

C’ (3,-6)

Step-by-step explanation:

Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis

By reflecting over the x-axis, the y-coordinate is bound to change in sign

So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)

We simply go on to negate the value of the y-coordinate

Mathematically if we apply these to the given points, what we get are the following;

A’ (5,-2)

B’ ( 1,-2)

C’ (3,-6)

4 0
2 years ago
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