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sattari [20]
3 years ago
6

If mean and median are close does it mean symmetrical

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0
They are not the same in a unimodal symmetrical distribution and they will never be !
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Whixh graph shows a plot of the complex number I -2?
Mrac [35]
Mona mona mona mona monq mona
5 0
3 years ago
[2x(3+5)+6]x4 what is the value of this expression
Gekata [30.6K]

Answer:

16x5+6x4

Step-by-step explanation:

(2x(3+5)+6)(x4)

=(2x(3+5)+6)(x4)

=(2x(3+5))(x4)+(6)(x4)

=16x5+6x4

5 0
2 years ago
Read 2 more answers
F(x)=9x-6<br> what is f(1)
Leto [7]
Hello,

Shall we begin?

<span>F(x)=9x-6
</span>
F(1) = 9 * 1 - 6
F(1) = 9 - 6
F(1) = 3

Answers: 3
8 0
3 years ago
Order Of operation.
Nikolay [14]

Answer

18(2)+12(2)-4(5)

36+24-20

60-20

40

Step-by-step explanation:

since they had two-18 yard passes and two 12 yard runs, that's the first part of the expression, and then they had four penalties that cost them 5 yards, and that was the last term. When you simplify, you end up with 40 yards gained.

In math

Passes: 18(2)

Runs: 12(2)

Penalties:4(5)

equation

18(2)*12(2)-4(5)

Hope it helped

7 0
3 years ago
Read 2 more answers
A survey of 1 comma 558 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying
sineoko [7]

Answer with explanation:

Let  p be the proportion of adults have heard of the new electronic reader.

Given claim : The accompanying technology display results from a test of the claim that 38​% of adults have heard of the new electronic reader.

i.e. p=0.38

Then , the set of hypothesis will be :-

H_0: p=0.38\\\\H_a:p\neq0.38

Since, the alternative hypothesis is two tailed , so the test is two-tailed test.

Also, it is given that the sample size : n=1558

Number of adults showed that they have heard of a new electronic reader=522

So the sample proportion for adults have heard of the new electronic reader : \hat{p}=\dfrac{522}{1558}\approx0.34



The test statistic for proportion is given by :-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\\Rightarrow\ z=\dfrac{0.34-0.38}{\sqrt{\dfrac{0.38(1-0.38)}{1558}}}\\\\\\\Rightarrow\ z=-3.25279036541\approx-3.25

By using standard normal distribution table , the P-value for two tailed test corresponds to the obtained z-value ==0.0011541

6 0
3 years ago
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