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lord [1]
2 years ago
13

#5: Solve the following equation 60=5r-4r+14 (Show Work Here)

Mathematics
1 answer:
BigorU [14]2 years ago
6 0

Answer:

r = 46  

Step-by-step explanation:

To solve the equation, solve for r by isolating the variable. Whatever you do to one side, do to the other.  

1) First, simplify the right side by combining like terms. Subtract the coefficients of the terms with the same variables. Subtract 5r by 4r.

60 = 5r-4r + 14\\60 = r + 14

2) Now, finally isolate r by subtracting both sides by 14.

60 = r + 14\\46 = r

So, r = 46.

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Please help me real quick ​
Eddi Din [679]

Answer:

x= 7

Step-by-step explanation:

11x-2 = 75

11(7) - 2

77 - 2 = 75

x= 7

3 0
3 years ago
Mr. Bulky’s Candy Emporium sells all candy items for $0.60 per ounce. Penny and Ruth each bought several different types of cand
exis [7]

Answer: what’s the rest of the question? You didn’t provide enough data…✨

Step-by-step explanation:

4 0
2 years ago
If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.
kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence lnv = -2t+ln 7\\v=7e^{-2t}

since velocity is rate of change of distance s we have

v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[

substitute t=0 and s=0

C=7/2

So solution for distance is

s(t) =\frac{-7}{2} (e^{-2t}-1)

4 0
3 years ago
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ddd [48]

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Ok

Step-by-step explanation:

5 0
2 years ago
Please explain I really need help
velikii [3]

Answer:

1. 1343 years

2. 9 hours

3. 39 years

Step-by-step explanation:

1. Given, half-life of carbon = 5730 years.

∴ λ = 0.693/half-life of carbon = 0.693/5730 = 0.000121

If N₀ = 100 then N = 85

Formula:- N = N₀*e^(-λt)

∴ 85 = 100 * e^(-0.000121t)

∴㏑(-0.85)=-0.000121t

∴ t = 1343 years

2. Given half-life of aspirin = 12 hours

λ = 0.693/12 = 0.5775

Also N₀ = 100 then 70 will disintegrate and N = 30 will remain disintegrated.

∴ 70 = 100 *e^(-0.05775t)

0.70 = e^(-0.05775t)

㏑(0.70) = -0.05775t

∴ t = 9 hours

3.  The population of the birds as as A=A₀*e^(kt)

Given that the population of birds fell from 1400 from 1000, We are asked how much time it will take for the population to drop below 100, let that be x years.

The population is 1400 when f = 0, And it is 1000 when f = 5

We can write the following equation :

1400 = 1000e^(5t).

∴1400/1000 = e^(5k)

∴ k = ㏑(1.4)/5

We need to find x such that 1400/100 = e^(xk)

14 = e^(xk)

∴ x = 39 years

5 0
3 years ago
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