Answer:
Step-by-step explanation:
a) H0: 
Ha: 
(Two tailed test at 5% significance level)
b) n=30
Mean difference = 
Std error of mean = 
b) Test statistic t = mean diff/std error = -1.552
df = 30-1 =29
p value=0.0657
c) Since p > 0.05 our signi. level, we accept null hypothesis.
There is no significant difference between the means.
d) Using critical value we find that test statistic is > critical value left
So accept H0
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The answers:
x = 1
y = -5
Answer:

Step-by-step explanation:
Given
One-eighth times three-elevenths
Required
Solve
One-eighth means 1/8
Three-elevenths means 3/11
So, mathematically; the above expression is represented as thus:

To solve this, we simply multiply the numerator and the denominator together.
After multiplying these together, the next is to check if the resulting can be simplified
If yes,we simplify it and if otherwise, we live it like that.
So,



At this point, the fraction can't be simplified any further.
Hence,

Answer:
B. ) x² + 4x + 3
Step-by-step explanation:
(f-g)(x) = f(x) - g(x) =
(2x²-5) - (x²-4x-8) =
2x² - x² + 4x + 8 - 5 =
x² + 4x + 3
<h3>Answer to Question 1:</h3>
AB= 24cm
BC = 7cm
<B = 90°
AC = ?
<h3>Using Pythagoras theorem :-</h3>
AC^2 = AB^2 + BC ^ 2
AC^2 = 24^2 + 7^2
AC^2 = 576 + 49
AC^2 = √625
AC = 25
<h3>Answer to Question 2 :-</h3>
sin A = 3/4
CosA = ?
TanA = ?
<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>
(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)
<h3>Using Pythagoras theorem :-</h3>
AC^2 = AB^2 + BC ^ 2
4² = AB² + 3²
16 = AB + 9
AB = √7cm
<h3>CosA = Adjacent side/Hypotenuse</h3>
= AB/AC
= √7/4
<h3>TanA= Opp. side/Adjacent side</h3>
=BC/AB
= 3/√7