Answer:
C
Step-by-step explanation:
Answer: 121
scores on a test have a mean of 67 and a standard devation of 10. michelle has a score of 87. convert michelle score to a z-scor
1 answer:
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<u>Part (a)</u>
The variable y is the dependent variable and the variable x is the independent variable.
<u>Part (b)</u>
The cost of one ticket is $0.75. Therefore, the cost of 18 tickets will be:
dollars
Now, we know that Kendall spent her money only on ride tickets and fair admission and that she spent a total of $33.50.
Therefore, the price of the fair admission is: $33.50-$13.50=$20
If we use y to represent the total cost and x to represent the number of ride tickets, the linear equation that can be used to determine the cost for anyone who only pays for ride tickets and fair admission can be written as:
......Equation 1
<u>Part (c)</u>
The above equation is logical because, in general, the total cost of the rides will depend upon the number of ride tickets bought and that will be 0.75x. Now, even if one does not take any rides, that is when x=0, they still will have to pay for the fair admission, and thus their total cost, y=$20.
Likewise, any "additional" cost will depend upon the number of ride tickets bought as already suggested. Thus, the total cost will be the sum of the total ride ticket cost and the fixed fair admission cost. Thus, the above Equation 1 is the correct representative linear equation of the question given.
Changing the equation into slope form: 
, where 
is the slope [gradient] and 
is the y-intercept.
The gradient is
and y-intercept is at 
Graphing using slope-intercept method:
a) The slope is a negative slope. The line will go 'down hill'
b) The line must pass the point (0, 490)
c) The line will intercept the x-axis at y = 0
So, x-intercept is at (735, 0)
The graph of this function is shown below. The intercepts are labelled at:
y = 490
x = 735
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Next month's profit equation
Rewriting this into slope-equation form
The gradient,, equals to
The y-intercept,, equals to 531
The equation still has the same gradient with last month's profit equation but different y-intercept.
-------------------------------------------------------------------------------------------------------------
A linear graph show points of (0, 300) and (450, 0)
We work out the slope:
Y-intercept at x = 0, so it's at y = 300
Equation
The gradient is
Graphing
a) The slope is a negative slope. The line will go 'down hill'
b) The line must pass the point (0, 490)
c) The line will intercept the x-axis at y = 0
So, x-intercept is at (735, 0)
The graph of this function is shown below. The intercepts are labelled at:
y = 490
x = 735
-----------------------------------------------------------------------------------------------------------
Next month's profit equation
Rewriting this into slope-equation form
The gradient,
The y-intercept,
The equation still has the same gradient with last month's profit equation but different y-intercept.
-------------------------------------------------------------------------------------------------------------
A linear graph show points of (0, 300) and (450, 0)
We work out the slope:
Y-intercept at x = 0, so it's at y = 300
Equation