GCF of them is 2w.
Hope this helps :)
Answer: 16 posters
Step-by-step explanation:
Monday - Had owned 16 posters
Tuesday - Bought 4 posters, adding up to 20
Wednesday - Half of the posters were destroyed, half of 20 is 10
Thursday - 10 posters remained.
Answer:
p =2 p=-18
Step-by-step explanation:
|p+8|
-------------- = 5
2
Multiply each side by 2
|p+8|
-------------*2 = 5*2
2
|p+8| =10
There is a positive and a negative solution
p+8=10 p+8=-10
Subtract 8 from each side
p+8-8=10-8 p+8-8=-10-8
p =2 p=-18
Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
Simply you can substitute theta=45 degrees (or any angle,not zero) in left hand side and right hand side.
or
using a^2 - b^2 =(a+b)(a-b)
= sin(2x+x)sin(2x-x)
= sin 3x sin x
