Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

We have
and
, because the dice are fair.
Now we use the assumption of independence to claim that

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:
- 2 in a unique way (1+1)
- 3 in two possible ways (1+2, 2+1)
- 4 in three possible ways
- 5 in three possible ways
- 6 in three possible ways
- 7 in two possible ways
- 8 in a unique way
This implies that the probabilities of the outcomes of
are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5
Answer:
sorry for points
Step-by-step explanation:
<u>4(x + 2) + 3 >= 27</u>
4x + 8 + 3 >= 27
4x + 11 >= 27
4x >= 16
<u>x >= 4</u>
All you have to do it do 60 - 35 = 25 dollars because they want to know if the original price would be 60 dollars and they wanna know the anwser if you took away 35 dollars. so then you just subtract