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Elina [12.6K]
3 years ago
9

In the expression 5a2 + 4x2 - 7a + 8y - 9 How many terms are there?

Mathematics
1 answer:
natta225 [31]3 years ago
5 0

Answer:

5 terms

Step-by-step explanation:

5a² is a term

4x² is a term

7a is a term

8y is a term

9 is a term

In total, there are 5 terms.

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Complete the problem​
nika2105 [10]

Answer:

The answer is C..........

4 0
3 years ago
Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for
KIM [24]

Answer:

a) The recurrence formula is P_n = \frac{109}{100}P_{n-1}.

b) The general formula for the population of Tacoma is

P_n = \left(\frac{109}{100}\right)^nP_{0}.

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write P_0 = 200 000. For the population in 2001 we will use P_1, for the population in 2002 we will use P_2, and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that P_0 is equal to P_1 plus 9% of the population of 2000. Notice that this can be written as

P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0.

In 2002, we will have the population of 2001, P_1, plus the 9% of P_1. This is

P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1.

So, it is not difficult to notice that the general recurrence is

P_n = \frac{109}{100}P_{n-1}.

b) In the previous formula we only need to substitute the expression for P_{n-1}:

P_{n-1} = \frac{109}{100}P_{n-2}.

Then,

P_n = \left(\frac{109}{100}\right)^2P_{n-2}.

Repeating the procedure for P_{n-3} we get

P_n = \left(\frac{109}{100}\right)^3P_{n-3}.

But we can do the same operation n times, so

P_n = \left(\frac{109}{100}\right)^nP_{0}.

c) Recall the notation we have used:

P_{0} for 2000, P_{1} for 2001, P_{2} for 2002, and so on. Then, 2016 is P_{16}. So, in order to obtain the approximate population of Tacoma in 2016 is

P_{16} = \left(\frac{109}{100}\right)^{16}P_{0} = (1.09)^{16}P_0 = 3.97\cdot 200000 \approx 794062

d) In this case we want to know when P_n>400000, which is equivalent to

(1.09)^{n}P_0>400000.

Substituting the value of P_0, we get

(1.09)^{n}200000>400000.

Simplifying the expression:

(1.09)^{n}>2.

So, we need to find the value of n such that the above inequality holds.

The easiest way to do this is take logarithm in both hands. Then,

n\ln(1.09)>\ln 2.

So, n>\frac{\ln 2}{\ln(1.09)} = 8.04323172693.

So, the population of Tacoma should exceed the 400 000 by the year 2009.

8 0
3 years ago
Read 2 more answers
Henry is conducting an experiment with 800 bacteria. He found the exponential growth rate to be 2.7% per hour. What is the amoun
joja [24]
Let's formulate an equation first. For exponential growth, we follow the formula. b = 800, r - 0.027. Hence,

y = 800(1+0.027)^t

Then, at t = 21, y will be determined
y = 800 (1+0.027)^21
y = 1399.81 = 1400

Thus, the amount of bacteria present after 21 hours is 1400.
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DiKsa [7]

Answer:

x = 44

Step-by-step explanation:

3x - 5 is complementary to y° so their sum is 180°

The angle with measure 127° is also complementary with y°

127 + y = 180

y = 53°

53 + 3x - 5 = 180

3x + 48 = 180

3x = 132

x = 44

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3 years ago
Write an expression that represents the quantity 5 more than a number
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6+7 is that good i hope so
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