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JulijaS [17]
2 years ago
14

The side of the square ABCD is 8 cm. The length ED of the rectangle EFGB is 10 cm. What is the length of FG

Mathematics
1 answer:
Charra [1.4K]2 years ago
4 0

Answer:

sqrt39

Step-by-step explanation:

Because AE is 5 because the square intersects by half based on the SSS theorem. Therefore we can use The Pythagorean Theorem and get 8^2-5^2 to get sqrt39

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A triangle has vertices (2, 1), (5, 1), and (5,5). What is the length of the longest side of the triangle?
Lerok [7]

Answer:

5,5

Step-by-step explanation:

it has the longest side

8 0
2 years ago
each of equal sides of an isosceles triangle is 4cm greater than its height .If the base of triangle is 24 cm ,calculate the per
Montano1993 [528]
<h3><u>Answer</u><u>:</u><u>-</u></h3>

192 cm²

<h3><u>Step</u><u> </u><u>by</u><u> step</u><u> explanation</u><u> </u><u>:</u><u>-</u></h3>

Let us take the height be x , then its side = x + 4. Now half of base will be 12 cm .

<u>According</u><u> to Pythagoras Theorem :- </u>

=> base² + perpendicular ² = hypontenuse ²

=> 12² + x² = (x+4)²

=> 144 + x² = x² + 16 + 8x

=> 8x = 144-16

=> 8x = 128

=> x = 128/8

=> x = 16 cm .

Hence the height of ∆ is 16 cm .So the area will be half the product of base and altitude.

= 1/2 * 16 cm * 24cm .

= 192 cm²

<h3><u>★</u><u> </u><u>Hence</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the </u><u>tria</u><u>ngle</u><u> is</u><u> </u><u>1</u><u>9</u><u>2</u><u> </u><u>cm²</u><u> </u><u>.</u></h3>
8 0
2 years ago
Solve for f.<br><br> f<br> 3<br> + -22<br> = -19<br><br><br> f =
IRISSAK [1]
F=1
Add 22 to both sides, then divide both sides by 3

3 0
2 years ago
Read 2 more answers
4. Find f(2) if f(x) = 2x + 1.
irina [24]

Answer:

X= .5 (decimal form)

X= 1/2 (Exact form)

6 0
2 years ago
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In the figure CD is the perpendicular bisector of AB . If the length of AC is 2x and the length of BC is 3x - 5 . The value of x
Dennis_Churaev [7]

Answer

Find out the value of x .

To proof

SAS congurence property

In this property two sides and one angle of the two triangles are equal.

in the Δ ADC and ΔBDC

(1) CD = CD (common side of both the triangle)

(2) ∠CDA = ∠ CDB = 90 °

( ∠CDA +∠ CDB = 180 ° (Linear pair)

as given in the diagram

∠CDA  = 90°

∠ CDB = 180 ° - 90°

∠ CDB = 90°)

(3) AD = DB (as shown in the diagram)

Δ ADC ≅ ΔBDC

by using the SAS congurence property .

AC = BC

(Corresponding sides of the congurent triangle)

As given

the length of AC is 2x and the length of BC is 3x - 5 .

2x = 3x - 5

3x -2x =5

x = 5

The value of x is 5 .

Hence proved


7 0
3 years ago
Read 2 more answers
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