X 2 +y 2 +4x−2y=−1space, x, start superscript, 2, end superscript, plus, y, start superscript, 2, end superscript, plus, 4, x, m
stepan [7]
The radius is 2.
We will rewrite this equation in center-radius form,
(x-h)²+(y-k²)=r²
where (h, k) is the center of the circle and r is the radius.
In order to do this, we will need to complete the square. We will first rewrite this with the x terms grouped together and the y terms grouped together:
x²+4x+y²-2y = -1
To complete the square for the x terms, we divide the coefficient b (as in bx) by 2:
4/2 = 2
Now we square this:
2²=4
We will add this to both sides of the equation (in order to maintain balance, we must add it to both sides):
x²+4x+4+y²-2y=-1+4
x²+4x+4+y²-2y=3
We have completed the square for the x terms. When we divided b by 2, that gave us the number we need, 2:
(x+2)²+y²-2y=3
Now we will do the same thing for the y terms. The b for our y terms is -2:
-2/2 = -1
(-1)²=1
So we will add 1 to both sides, and use -1 in the finalized form:
(x+2)²+y²-2y+1=3+1
(x+2)²+(y-1)²=4
We can see that the center would be located at (-2, 1) and the radius is √4=2.
Hopefully this helps and makes sense to you if you don’t understand ask another question to me or anyone hehe
Gosh, the list of choices to pick from is so short !
The dimensions of the rectangle are
' L ' and ' 10/L ' .
I guarantee it.
Chris will solve his problem by dividing because using division can tell you a missing factor, and vice versa. 10 / 10 = 1, so 1 is the missing factor. Then Chris can multiply: 10 X 1 = 10. So, Chris will divide, then multiply.
Step-by-step explanation: