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kkurt [141]
3 years ago
7

Convert 3.50 liters to mL.​

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0
Your answer is 3500 mL
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Ajar holding 36 coins, only nickels and quarters, is worth $6.20. There are eight more quarters than there are nickels. How many
Nonamiya [84]

Answer:

  14

Step-by-step explanation:

Let n represent the number of nickels. Then the number of quarters is 36-n. The difference is ...

  (36-n) -n = 8 . . . . . 8 more quarters than nickels

  18 -n = 4 . . . . . . . divide by 2

  14 = n . . . . . . . . add n-4 to both sides

There are 14 nickels in the jar.

_____

<em>Additional comment</em>

The problem supplies more information than is needed for a solution. You can work this as a "sum and difference" problem, as we have above, or you can work it as a "mixture" problem where the total coin value comes into play. Any two of the three given relations will give a solution.

  n + q = 36 . . . . . . . number of coins

  5n +25q = 620 . . . value of coins (in cents)

  q -n = 8 . . . . . . . . difference in number of coins

6 0
3 years ago
Complete this quiz to finish the assignment for 3A - Geometry Pap due on Mar 23, 2021
Natalija [7]

Answer:

What is the Picture?

Step-by-step explanation:

8 0
3 years ago
Which of the following expressions is 0.00012 written in scientific notation? A. 0.12 × 10^-3 B. 1.2 × 10^-4 C. 12 × 10^-5 D. 1.
In-s [12.5K]

Answer:

B. 1.2 x 10^{-4}

Step-by-step explanation:

Scientific notation is a way of writing very large or very small numbers. A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10. For example, 650,000,000 can be written in scientific notation as 6.5 ✕ 10^8.  Or, in this case it's the opposite since we have a negative number. Since it's a decimal it's multiplied by 10 still but the exponent is negative. All we need to do to find what the exponent would be in this case is to count the number of zeros before the "12." There are 4 zeros before the 12. So your exponent would be -4. Now all we need to do is write out "equation" per say.

1.2 x 10^-4

<u>Hope this helps and have a nice day!</u>

5 0
3 years ago
Read 2 more answers
The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped
kakasveta [241]

Check the picture below.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2  = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0
3 years ago
Calculate the circumference of the circle. Use 3.14 for pi. I WILL MARK BRAINLIEST
Harrizon [31]

Answer:

The answer would be B

Step-by-step explanation:

C=2(pi)r

C=25.12

8 0
3 years ago
Read 2 more answers
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