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Harlamova29_29 [7]
3 years ago
15

Each side of a square is increasing at a rate of 6 cm/s. at what rate is the area of the square increasing when the area of the

square is 36 cm2?\
Mathematics
1 answer:
katrin [286]3 years ago
8 0
A = s^2
A' = 2s*s'

When the area is 36 cm^2, the side (s) is 6 cm. The area is increasing at the rate
A' = 2(6 cm)*(6 cm/s) = 72 cm^2/s
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What are the solutions of the equation?
Maksim231197 [3]

Answer:

x₁ = √15

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Step-by-step explanation:

x² - 15 = 0

x² = 15

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3 years ago
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irinina [24]

Answer: 2

Step-by-step explanation:

Vertical asymptotes can be solved by setting the denominator equal to zero.

x(x+1) = 0

Solve for 0 now by setting both x and x+1 equal to zero

x = 0

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x = -1

Because there are two factors in the denominator, the answer would be two.

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8 0
2 years ago
If f(x) = 2x+6 and g(x)= x3 what is (g f)(0)?
GuDViN [60]

Answer:

27

Step-by-step explanation:

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1 year ago
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Ilya [14]
$70.45 Is the correct answer
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2 years ago
4b+3=−9 i need help it is inportant
Fantom [35]

Answer:

b=-3

Step-by-step explanation:

4b+3=-9

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subtract 3 from both sides like so. 3-3 cancels out. -9-3=-12.

4b=-12

youre left with 4b=12 so DIVIDE 4b by 4 and -12 by 4

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b=-3

plug -3 in for b to make sure its correct

4(-3)+3=-9

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5 0
3 years ago
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