Answer:
x = 25
Step-by-step explanation:
Given:
Since ∠A is equivalent to ∠B...
Open the parenthesis:
Add 8 both sides:
Simplify both sides:
Subtract 6x both sides:
Simplify both sides:
The answer is: The population age 12 or under was 3680.
<h2>Why?</h2>If in 2010 the population of Kignsford was 8000, and by 2014 the population had increased by 15% we need to calculate the total population and then, calculate how many people was age 12 or under.
We must remember that we cannot work with percentage values, so, to make 15% a real number, we need to divide it by 100:
So,
Calculating the population by 2014, we have:
Then, substituting we have:
Now, calculating the population that was age 12 or under, knowing that it was 2/5 of the total population, we have:
So, the population age 12 or under was 3680.
Have a nice day!
Answer:
a) X Freq. Rel Freq.
__________________________
0 7 (7/58) = 0.121
1 10 (10/58)=0.172
2 13 (13/58) =0.224
3 14 (14/58)=0.241
4 6 (6/58)=0.103
5 3 (3/58)=0.052
6 3 (3/58)=0.052
7 1 (1/58) =0.017
8 1 (1/58)=0.017
_________________________
Total 58 1.00
b)
Step-by-step explanation:
Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:
2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,
0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,
5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3
(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)
For this case first we order the dataset on increasing way and we got:
0 0 0 0 0 0 0
1 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2 2 2 2 2 2 2 2
3 3 3 3 3 3 3 3 3 3 3 3 3 3
4 4 4 4 4 4
5 5 5
6 6 6
7
8
And we can construct the following table:
X Freq. Rel Freq.
__________________________
0 7 (7/58) = 0.121
1 10 (10/58)=0.172
2 13 (13/58) =0.224
3 14 (14/58)=0.241
4 6 (6/58)=0.103
5 3 (3/58)=0.052
6 3 (3/58)=0.052
7 1 (1/58) =0.017
8 1 (1/58)=0.017
_________________________
Total 58 1.00
(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)
For this case this proportion would be:
