A line intersects the points( 12,2) and (6, -8) what is the slope of the line in simplest form
1 answer:
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Recall that the domain of a function is the set of all x values of the function for which the function is defined.
Given that
and 
Given that
For the function to be undefined, the denominator should be zero
i.e. 2x = 0 which means that x = 0
Thus, the domain of the function is all real values of x except 0.
Therefore, the restriction is x ≠ 0.
Given that
For the function to be undefined, the denominator should be zero
i.e.
For x = 2,
Also, for x = 1
Thus, the domain of the function is all real values of x except 1 and 2.
Therefore, the restriction is x ≠ 1, 2.
Given that
For the function to be undefined, the denominator should be zero
i.e.
For x = -2,
.
Thus, the domain of the function is all real values of x except -2.
Therefore, the restriction is x ≠ -2.
Given that
There is no value of x, for which the function is undefined.
Thus, the domain of the function is all real values of x.
Therefore, there is no restrictions to the domain of the function.
Given that
For the function to be undefined, the denominator should be zero
i.e.
Thus, the domain of the function is all real values of x except -1.
Therefore, the restriction is x ≠ -1.
Given that
Given that
For the function to be undefined, the denominator should be zero
i.e. 2x = 0 which means that x = 0
Thus, the domain of the function is all real values of x except 0.
Therefore, the restriction is x ≠ 0.
Given that
For the function to be undefined, the denominator should be zero
i.e.
For x = 2,
Also, for x = 1
Thus, the domain of the function is all real values of x except 1 and 2.
Therefore, the restriction is x ≠ 1, 2.
Given that
For the function to be undefined, the denominator should be zero
i.e.
For x = -2,
Thus, the domain of the function is all real values of x except -2.
Therefore, the restriction is x ≠ -2.
Given that
There is no value of x, for which the function is undefined.
Thus, the domain of the function is all real values of x.
Therefore, there is no restrictions to the domain of the function.
Given that
For the function to be undefined, the denominator should be zero
i.e.
Thus, the domain of the function is all real values of x except -1.
Therefore, the restriction is x ≠ -1.
The correct answer is B
Let us do the first product,
We have;
We can re-group the sign and the numbers to obtain;
But we know that; negative times negative is positive. So the product becomes,
Similarly for the second product,
We have;
We can again re-group the sign and the numbers to obtain;
But we know that; negative times negative is positive. So the product becomes,
Putting all together gives,
Finally, positive times positive will also give positive. That is,
Let us do the first product,
We have;
We can re-group the sign and the numbers to obtain;
But we know that; negative times negative is positive. So the product becomes,
Similarly for the second product,
We have;
We can again re-group the sign and the numbers to obtain;
But we know that; negative times negative is positive. So the product becomes,
Putting all together gives,
Finally, positive times positive will also give positive. That is,