1. 12×20÷(4+16)=
240÷20=12
2. (31-3)÷14+3 power of 2
28÷14+9
2+9=11
Answer:
May be the second one
Step-by-step explanation:
hope it'll help ☺️
Answer:
A. 3 < t < 9
Step-by-step explanation:
When the particle is moving to the right, the velocity is positive.
To find the velocity, take the derivative of s(t) with respect to t.
s(t) = -t³/3 + 13t²/2 − 30t
s'(t) = -t² + 13t − 30
Find when the velocity is 0.
0 = -t² + 13t − 30
0 = t² − 13t + 30
0 = (t − 3) (t − 10)
t = 3, 10
Check the sign of s'(t) in each interval.
0 < t < 3, s'(t) < 0
3 < t < 9, s'(t) > 0
The particle moves to the right when 3 < t < 9.
Hi there!
We can find the answer by factoring the equation, then setting them up equal to zero.
x² - 7x + 12 = 0
(x - 3)(x - 4) = 0
x - 3 = 0 x - 4 = 0
x = 3 x = 4
So you have two real solutions for the equation x² - 7x + 12 = 0.
Hope this helped! :)
Answer:
-27÷(-3)-9
=0
Step-by-step explanation:
Hope this helps you.
