I guess the correct answer to the blank is round.
You can rotate a selected graphic by dragging a round rotation handle.
Answer: D, C, E, are the answers! good luck.
Explanation:
Answer:
int sumid=0; /* Shared var that contains the sum of the process ids currently accessing the file */
int waiting=0; /* Number of process waiting on the semaphore OkToAccess */
semaphore mutex=1; /* Our good old Semaphore variable ;) */
semaphore OKToAccess=0; /* The synchronization semaphore */
get_access(int id)
{
sem_wait(mutex);
while(sumid+id > n) {
waiting++;
sem_signal(mutex);
sem_wait(OKToAccess);
sem_wait(mutex);
}
sumid += id;
sem_signal(mutex);
}
release_access(int id)
{
int i;
sem_wait(mutex);
sumid -= id;
for (i=0; i < waiting;++i) {
sem_signal(OKToAccess);
}
waiting = 0;
sem_signal(mutex);
}
main()
{
get_access(id);
do_stuff();
release_access(id);
}
Some points to note about the solution:
release_access wakes up all waiting processes. It is NOT ok to wake up the first waiting process in this problem --- that process may have too large a value of id. Also, more than one process may be eligible to go in (if those processes have small ids) when one process releases access.
woken up processes try to see if they can get in. If not, they go back to sleep.
waiting is set to 0 in release_access after the for loop. That avoids unnecessary signals from subsequent release_accesses. Those signals would not make the solution wrong, just less efficient as processes will be woken up unnecessarily.
Where is the following banks that is listed?
Answer: User the insert screen recording control
Explanation:
Since Ishmael wants to capture a selected potion of his screen l, after which he'll then capture the action that he performs on that selected portion, he should use the insert screen recording control.
It should be noted that on most keyboards, there's an "insert screen" button. Also, Ishmael can simply open the window that he wants to screenshot and then click the screenshot button.
Therefore, the correct option is B.
