Toretto and O’Conner graphed two different quadratic functions in vertex form. Toretto graphed f(x)=(x+3)^2+1 and O’Conner graph

Question

3 years ago

14

ed g(x) =-(x-3)^2+1 . Both of them drew the same graph.

1 answer:

Len [333] · Answer 1 · 2022-03-20T18:28:14+03:00

Len [333]3 years ago

5 0

Yo sup??

By observing the graph we can say that minimum value of Toretto graph occurs at x=-3

whereas the minimum value of OConner graph occurs at x=3 .

In the given figure the minimum value is at x=3

therefore OConner is correct because the vertex is (3,1)

Hope this helps