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3 years ago

1. The handwritten rough draft of your book report is 4 pages long. Typing

Mathematics

1 answer:

alexandr402 [8]3 years ago

3 0

Answer:

The report is 960 words long.

Step-by-step explanation:

The handwritten book report is 4 pages long and the typed report is 3 pages long.

Now, it is given that typing at a steady rate of 20 words per minute, it takes 48 minutes to enter the report into soft copy.

So, the required number of words of the report is (20 × 48) = 960 words.

Hence, the report is 960 words long. (Answer)

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1) 28 + 3[{12 + 2 (14~4) = 5} - 6] 3

nasty-shy [4]

Answer:

Step-by-step explanation:

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3 years ago

Use the graph to determine

Sonja [21]

Answer:

a. Domain : All Real Numbers

b. Range: y≥ -1

c. The x-intercepts are (0,0) and (-4,0)

d. The y-intercept is (0,0).

e. f(2)=3

f(-2)=-1

Step-by-step explanation:

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3 years ago

Surface area of this prism ?

beks73 [17]

Answer:The surface area of this prism is the squares

Step-by-step explanation:the reason being is that the square on top is the surface of the prism

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3 years ago

Read 2 more answers

State the intervals for which the given quadratic is positive and when it is negative.

goblinko [34]

Answer:

Positive at (-9, 2)
Negative at ( -oo, -9) or (2, + oo)

Step-by-step explanation:

Given function

y= -2x^2 - 14x + 36

Getting zero's

-2x^2 - 14x + 36 = 0
x^2 + 7x - 18 = 0

x = ( -7 ± √(49 +72))/2 = ( -7 ± 11)/2
x = - 9 and x = 2

As the x^2 has negative coefficient, the function is positive between -9 and 2

- 9 < x < 2 or
(-9, 2)

And it is negative at:

x < -9 and
x > 2
or
( -oo, -9) or (2, + oo)

3 0

3 years ago

D(x)=(x^2-12x+20)/(3x)

krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

Explanation:

d(x) = $\frac{x^{2}-12x+20}{3x}$

= $\frac{(x-2)(x - 10)}{3x}$

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0

÷3 ÷3

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

(1/3)x - 4
3x) x² - 12x + 20
x²
-12x
-12x
20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4

6 0

3 years ago