Answer:
Degree = 1
Step-by-step explanation:
Given:
The differential equation is given as:

The given differential equation is of the order 2 as the derivative is done 2 times as evident from the first term of the differential equation.
The degree of a differential equation is the exponent of the term which is the order of the differential equation. The terms which represents the differential equation must satisfy the following points:
- They must be free from fractional terms.
- Shouldn't have derivatives in any fraction.
- The highest order term shouldn't be exponential, logarithmic or trigonometric function.
The above differential equation doesn't involve any of the above conditions. The exponent to which the first term is raised is 1.
Therefore, the degree of the given differential equation is 1.
Answer:
B
Step-by-step explanation:
have a good day and stay safe
well, let's take a peek, "m" is drawn on the x-axis most likely and H(m) is drawn on the y-axis, making a straight line.
so at m = -5, namely 5 minutes before he was told to go home, the kite was 375 meters up.
then he was told to go home, when m = 0, and the kite was 300 meters up.
now, as far as the other numbers, m = 5, 5 minutes after he was told, the kite was 225 m up, then 10 minutes later, then 15 minutes later then 20 minutes later m = 20, the kite was at 0, namely on the ground, he already had rolled up all the kite string that he was coiling up, so he can pack it in his carriage bag and go home.
It would be C=(<span>πr)r. Hope i helped!</span>
The data cannot be modeled by a linear equation because the rate of change is not constant. This can be seen in the fact that when you increase x from 1 to 2, you subtract 3 from the y-values. However, as you add 2 more, you continue to subtract 3 from the y-values. If the function were a linear function, we would likely subtract 6 from the y-values, since that would form a constant ratio.
You can even look at the fact that as we increased the x by 4, we continued to decrease the y by 3. This does not form a constant ratio, and is thus the data could not be modeled by a linear function.