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hram777 [196]
3 years ago
8

What is the equation for this graph?

Mathematics
1 answer:
Alla [95]3 years ago
4 0

Answer:

negative 5 and positive 4 is the answer

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Please help if possible. Thank you!
Shtirlitz [24]

Answer:15 pi

Step-by-step explanation:

The scope is 10(r)*2*pi

XPY is 3 quarters of the slope, which equals to 0.75*20*pi=15pi

6 0
3 years ago
Read 2 more answers
The perimeter of an isosceles triangle is 7.5m, and the length of a leg is 2m. Find the length of the base.
seraphim [82]
The legs of an isosceles triangle are congruent; they have the same length, so if one leg measures 2 m, the other leg also measures 2 m.

2m + 2m + b = 7.5 m

b + 4 m = 7.5 m

b = 3.5 m

The length of the base is 3.5 m.
5 0
3 years ago
Use f(x)=1/2x and f^-1(x)=2x to solve the problems f^1(-2), f(-4), f(f^-1(-2)?
neonofarm [45]
F^1(-2) = 2(-2) = -4
f(-4) = 1/2 * -4 =  -2

f(f^-1(x)) = x    so answer is  -2
8 0
3 years ago
Read 2 more answers
OB is the bisector of AD and EC. . EO = 2x – 20 and OC = 70 – x. Solve for x.
mixas84 [53]
<span>We know that OB bisects EC where they intersect would be at point O, 
so the two lengths EO and OC must be equal. 

2x - 20 = 70 - x 

</span>[adding x + 20 to each side] 

2x - 20 + x + 20 = 70 - x + x + 20

[simplifying]

<span>3x = 90 

</span>[dividing each side by 3]
<span>
x = 30 would be the answer</span>
4 0
3 years ago
Diagram 2 shows a piece of rectangular card in grey colour
Ilya [14]

Solution:

we have given the length of the rectangular card-

x + 5  \: cm

and, width-

7 \: cm

now, the area of the card will be- length×width.

so, we have-

(x + 5) \times 7 \: cm^{2}  \\ 7x + 35 \: cm^{2}

we also have given the length of ribbon-

7 \: cm

and, width-

y \: cm

so, area of the ribbon is-

length×width

7 \times y \: cm^{2}  \\ 7y \: cm^{2}

now the area of shaded gray region will be-

7x + 35 - 7y

Hence, the required expression would the above expression.

6 0
3 years ago
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