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3 years ago

What happens when money supply decreases?

1 answer:

8 0

Therefore aggregate demand will increase. The reverse will be true when money supply decreases. That is a decrease in the money supply will lead to a decrease in the amount of money that people and firms will hold and as a result they will spend less. This will cause aggregate demand to decrease. YOUR WELCOME

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Marty is moody, manipulative, unstable, lacks a clear sense of identity, and often clings to others. He wants to have close rela

umka2103 [35]

Answer: Borderline personality disorder

Explanation:

Since Marty is moody, manipulative, unstable, lacks a clear sense of identity, and often clings to others, this implies that Marty might be diagnosed with the borderline personality disorder.

Borderline personality disorder is a mental disorder characterised whereby the person affected has unstable behavior, moods, and relationships. In this case, Marty will be instable, impulsive, insecure, and have a feeling of worthlessness.

The treatment of borderline personality disorder is usually through talk therapy or medication.

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3 years ago

In his painting "Lady Liberty Leading

Kay [80]

Answer:

B. uninhibited freedom of speech

Explanation:

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2 years ago

SODNRITTAI unscrambled

BARSIC [14]

Answer.

i think traditions

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3 years ago

The ocean is a large body of water with an enormous mass, m. The air by the ocean rapidly changes temperature as day turns to ni

SpyIntel [72]

Answer: the ocean will not change temp. As quickly as the air because it takes much more energy to change the temp. Of water.

Explanation:

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3 years ago

Slope integrals for calculus, having trouble need all the help I can get

Harlamova29_29 [7]

(1) The integral is straightforward; x ranges between two constants, and y ranges between two functions of x that don't intersect.

$\displaystyle\int_{-2}^1\int_{-x}^{x^2+2}\mathrm dy\,\mathrm dx$

(2) First find where the two curves intersect:

y ² - 4 = -3y

y ² + 3y - 4 = 0

(y + 4) (y - 1) = 0

y = -4, y = 1 → x = 12, x = -3

That is, they intersect at the points (-3, 1) and (12, -4). Since x ranges between two explicit functions of y, you can capture the area with one integral if you integrate with respect to x first:

$\displaystyle\int_{-4}^1\int_{y^2-4}^{-3y}\mathrm dx\,\mathrm dy$

(3) No special tricks here, x is again bounded between two constants and y between two explicit functions of x.

$\displaystyle\int_1^5\int_0^{\frac1{x^2}}\mathrm dy\,\mathrm dx$

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3 years ago