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Nookie1986 [14]
3 years ago
14

If x^2+y^2 =25 and dy/dt =6, find dx/dt when y=4

Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0
2x dx/dt +2y dy/dt =0
x dx/dt +y (6)=0
dx/dt= -6y/x
dx/dt= -6*4 /x
dx/dt=-24/x
<span>also from the given equation x^2= 25-16=9 or x=3
using this we get</span>
dx/dt=-24/3 =-8

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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
puteri [66]

To find "s", you can use the Pythagorean theorem(which you can only use for right triangles):

a² + b² = c²               (c is the hypotenuse/the longest side of the triangle)


t = 18  (hypotenuse)

r = 12

s = ?

Plug in the numbers into the equation

a² + b² = c²

(12)² + b² = (18)²

144 + b² = 324        Subtract 144 on both sides

b² = 180           Square root both sides

b = √180  or  13.4

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Answer:

Not sure if this is correct but maybe it is 34?

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Step-by-step explanation:

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t = 64/32

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