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aleksklad [387]
3 years ago
9

If sin=3/5 then what does tan equal

Mathematics
2 answers:
daser333 [38]3 years ago
8 0

Answer:

Not sure if this is correct but maybe it is 34?

JulijaS [17]3 years ago
6 0

Answer: tan(x)=\±\frac{3}{4}

Step-by-step explanation:

You know that sin(x)=\frac{3}{5} and you can identify that. Then:

sin^2(x)=(\frac{3}{5})^2

sin^2(x)=\frac{9}{25}

Remember that:

cos^2(x)=1-sin^2(x)

Then cos^2(x) is:

cos^2(x)=1-\frac{9}{25}\\\\cos^2(x)=\frac{16}{25}

Apply square root to both sides to find cos(x):

\sqrt{cos^2(x)}=\±\sqrt{\frac{16}{25}}\\cos(x)=\±\frac{4}{5}

Remember that:

tan(x)=\frac{sin(x)}{cos(x)}

Then, this is:

tan(x)=\frac{\frac{3}{5}}{\±\frac{4}{5}}

tan(x)=\±\frac{3}{4}

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Quadrilateral ABCD is inscribed in a circle. m∠A is 64°, m∠B is (6x + 4)°, and m∠C is (9x − 1)°. What is m∠D?
Flauer [41]

Answer:

The m∠D is 98° ⇒ answer D

Step-by-step explanation:

* Lets revise some facts in the circle

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- It is called a cyclic quadrilateral

- Every two opposite angles in it are supplementary means the

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∵ ABCD is inscribed in a circle

∴ ABCD is a cyclic quadrilateral

∵ ∠A and ∠C are opposite angles in the cyclic quadrilateral ABCD

∴ ∠A and ∠C are supplementary

∴ m∠A + m∠C = 180°

∵ m∠A = 64°

∵ m∠C = (9x - 1)°

∴ 64 + (9x - 1) = 180 ⇒ simplify

∴ 63 + 9x = 180 ⇒ subtract 63 from both sides

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∴ x = 13

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∵ m∠B = (6x + 4)°

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∴ m∠B = 6(13) + 4 = 78 + 4 = 82°

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∵ ∠B and ∠D are opposite angles in the cyclic quadrilateral ABCD

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∴ m∠B + m∠D = 180°

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∴ 82° + m∠D = 180° ⇒ subtract 82° from both sides

∴ m∠D = 98°

* The m∠D is 98°

3 0
4 years ago
Equation C: y = 6x + 9
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Answer:

no solution

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8 0
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