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3 years ago

Finding X in triangle

Mathematics

1 answer:

Nat2105 [25]3 years ago

6 0

Answer:

x is 5 cm as the entire base is 10 cm, so 10/2 = 5

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What does Sin mean in geometry

Darya [45]

Answer:

in mathematics, the sine is a trigonometric function of an angle.

Step-by-step explanation:

The sine of an acute angle is defined in the context of a right triangle: for the specified angle, it is the ratio of the length of the side that is opposite that angle to the length of the longest side of the triangle (the hypotenuse).

Fixed point: 0

Critical point: kπ + π/2

Inflection point: kπ hope this helps you :)

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4 years ago

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Help!! Please!!!!!!!

JulsSmile [24]

Step-by-step explanation:

I think it's 27.6 because I added them the took them away from the number that where late. Then got 27.6% of them and got the same answer

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3 years ago

A(c-b)=d solve for c

Salsk061 [2.6K]

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3 years ago

Lydia rode the school bus for a total of 29 miles each day. How many miles did she ride the school bus over 180 days?

Savatey [412]

Answer:

5220 miles

Step-by-step explanation:

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3 years ago

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In a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2. Section 05.01 Ex

jasenka [17]

Answer:

95% confidence interval for the mean efficiency is [84.483 , 85.517].

Step-by-step explanation:

We are given that in a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2.

So, the pivotal quantity for 95% confidence interval for the population mean efficiency is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\mu$ = sample average efficiency = 85

$\sigma$ = sample standard deviation = 2

n = sample of motors = 60

$\mu$ = population mean efficiency

So, 95% confidence interval for the mean efficiency, $\mu$ is ;

P(-2.0009 < $t_5_9$ < 2.0009) = 0.95

P(-2.0009 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.0009 ) = 0.95

P( $-2.0009 \times {\frac{s}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.0009 \times {\frac{s}{\sqrt{n} }$ ) = 0.95

P( $\bar X -2.0009 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.0009 \times {\frac{s}{\sqrt{n} }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.0009 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.0009 \times {\frac{s}{\sqrt{n} }$ ]

= [ $85 -2.0009 \times {\frac{2}{\sqrt{60} }$ , $85 +2.0009 \times {\frac{2}{\sqrt{60} }$ ]

= [84.483 , 85.517]

Therefore, 95% confidence interval for the population mean efficiency is [84.483 , 85.517].

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3 years ago