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kvasek [131]
2 years ago
5

4X-8 + 6x +13= 90 ¿cual es le resultado ?

Mathematics
1 answer:
eimsori [14]2 years ago
4 0
4x - 8 + 6x + 13 = 90
4x + 6x = 90 + 8 - 13
10 x = 85
10x/10 = 85/10
x = 8.5
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The equation 2(5+7) = (2•5) + (2•7) illustrates what property?
wel

In this question, you're trying to figure out what property is being represented.

Your answer would be the Distributive Property

This is your answer because as you can see, you are "distributing" the 2 to the variables inside the parenthesis.

When you distribute the number, you would be multiplying, in which in this case there is multiplication.

Therefore, Distributive property would be the correct answer.

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3 years ago
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What is the solution of quadratic system of equations ?
kobusy [5.1K]

Answer:

(- 1, 1) and (- 5, - 35)

Step-by-step explanation:

since both equations express y in terms of x, equate the right sides

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x + 1 = 0 ⇒ x = - 1

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x = - 5 : y = (- 5)² + 15(- 5) + 15 = 25 - 75 + 15 = - 35 ⇒ (- 5, - 35 )

None of the given options



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3 years ago
Help please pre calculus
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As per the concept of probability, there are 4,717,440 number of passwords are possible.

Probability:

In statistics, probability refers the favorable outcome of the particular event.

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A password to a computer consists of 6 characters: a digit, a letter, a digit, a letter, a digit, and a letter in that order, where the numbers from 1 through 9 are allowed for digits.

Here we need to find how many different passwords are possible.

Total number of characters = 6

According to this, each password would have

5 digits of 10 digits: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], and

one of 26 letters: [A to Z].

Here there is no repeats are allowed, and assuming only upper case letters are valid and the letter is the last character, then we can form 10*9*8*7*6 * 26 = 786,240 such passwords.

If the repetition is allowed then number of possible passwords is

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brainly.com/question/11234923

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4 0
1 year ago
4. La figura se muestra un armazón arqueado de 50 metros de longitud con las alturas indicadas. Los "tirantes" verticales están
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verticales están a 12 metros uno del otro. Si tanto la parte superior como la inferior del arco son arcos de parábola, redondeo hasta el metro más cercano la suma de longitudes de los tirantes verticales e inclinados.

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