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lys-0071 [83]
3 years ago
9

A ruler is 12 inches long.what is the length of this ruler in centimeters

Mathematics
2 answers:
lawyer [7]3 years ago
8 0
I think it is 30.48 because i looked it up 
dexar [7]3 years ago
7 0
It's 30.48 cause each inch is 2.54 centimeters and times it by 12 =30.48
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Solve for the variable in the following inequality<br><br> 18 ≥ 6x
baherus [9]

Answer:

3 <u>> </u>x

Step-by-step explanation:

(Sorry if im wrong)

Divide both sides by 6

18/6 <u>></u> 6x/6

3 <u>></u> x

6 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
Zach is 6 inches shorter than two times his cousin’s height, c. How tall is Zach? To see what Gabriel did wrong, consider that c
irakobra [83]

Answer:

74 inches

Step-by-step explanation:

If his cousin is 40 inches tall, and Zach is 6 inches less than twice his height, solve for 40*2-6, which is 74.

3 0
2 years ago
What is the image of the point (4,-2) after a rotation 270 degree clockwise about the origin?
vaieri [72.5K]
The equivalent 90° CCW rotation maps (x, y) to (-y, x).
(4, -2) becomes (2, 4) after rotation.
4 0
3 years ago
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Which expression is equivalent to sec^2x − 1? a. cot2x b. tan2x c. csc2x d. cos2x
Nesterboy [21]
Sec^2 x - 1 = tan^2x

Proof:
Sec^2x = 1+ tan^2x

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<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting : 
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side 
4 0
3 years ago
Read 2 more answers
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